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3 years ago

6

A High School is currently 700 students and increases at an annual rate of 3.5% per year

1 answer:

Cerrena [4.2K]3 years ago

7 0

Answer:

f(t) = 700(1.035)^t.

Step-by-step explanation:

Initial value is given as 700 students and this corresponds to time t = 0.

The growth factor is 1 plus 3.5% = 1.035.

The time t is in years.

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You and a friend each have a collection of tokens. Initially, for every 8 tokens you had, your friend had 3. After you give half

vlada-n [284]

If your friend now has 18 that means you had 48, as mentioned above, you had given half of your tokens, half of 48 is 24. =24

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3 years ago

Given a=5 b=12 c=13 5²+12²=13²

Advocard [28]

Answer:

a^2+b^2=a(2)^1.5

Step-by-step explanation:

im not sure, just seems right

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3 years ago

Grandma has 14 red roses and 7 pink roses how many more red roses than pink does she have explain how you solve the promblem

Helga [31]

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3 years ago

Consider the function f(x) = ex and the function g(x), which is shown below. How will the graph of g(x) differ from the graph of

SIZIF [17.4K]

Answer: Option C

Step-by-step explanation:

If the graph of the function $g(x)=f(x) +b$ represents the transformations made to the graph of $y= f(x)$ then, by definition:

If $b> 0$ the graph moves vertically upwards.

If $b$ the graph moves vertically down

In this problem we have the function $g(x)=e^x+5$ and our parent function is $f(x) = e^x$

therefore it is true that $b =5 > 0$

Therefore the graph of $f(x)=e^x$ is moves vertically upwards by a factor of 5 units.

The answer is the Option C: "The graph of g(x) is the graph of f(x) shifted up 5 units"

6 0

3 years ago

Please help if you can thanks ^^

Neko [114]

Given:

AD is an angle bisector in triangle ABC. $m\angle CAB=44^\circ, m\angle ACB=72^\circ, m\angle ABC=64^\circ$ .

To find:

The value of $m\angle ADC$ .

Solution:

AD is an angle bisector in triangle ABC.

$m\angle CAD=m\angle BAD=\dfrac{m\angle CAB}{2}$

$m\angle CAD=m\angle BAD=\dfrac{44^\circ}{2}$

$m\angle CAD=m\angle BAD=22^\circ$

According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees.

Using angle sum property in triangle CAD, we get

$m\angle CAD+m\angle ADC+m\angle ACB=180^\circ$

$22^\circ+m\angle ADC+72^\circ=180^\circ$

$m\angle ADC+94^\circ=180^\circ$

$m\angle ADC=180^\circ-94^\circ$

$m\angle ADC=86^\circ$

Therefore, the angle of angle ADC is $86^\circ$ .

3 0

3 years ago