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2 years ago

Which shows one way to determine the factors of 4x3 + x2 - 8x - 2 by grouping?

Mathematics

2 answers:

sergejj [24]2 years ago

8 0

Answer:

(x^2-2)(4x+1)

Step-by-step explanation:

4x^3 + x^2 - 8x - 2

Group:

(4x^3 + x^2)+( - 8x - 2)

Factor out as much as possible: (The GCF)

x^2(4x+1)-2(4x+1)

Regroup:

(x^2-2)(4x+1)

mr Goodwill [35]2 years ago

3 0

Answer:

(4x+1)(x²-2)

Step-by-step explanation:

one way to determine the factors of 4x^3 + x^2 - 8x - 2 by grouping:

x²(4x+1)-2(4x+1)

(4x+1)(x²-2)

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Find the solution to the system of equations below.<br> 2y = 2x - 8<br> 2x + y = 5

ladessa [460]

Answer:

The solution to the system of equations is:

(x, y) = (3, -1)

The graph is attached below.

Step-by-step explanation:

Given the system of equations

$2y = 2x - 8$

$2x + y = 5$

Let us solve the system of equations using the elimination method

$\begin{bmatrix}2y=2x-8\\ 2x+y=5\end{bmatrix}$

Arrange equation variables for elimination

$\begin{bmatrix}2y-2x=-8\\ y+2x=5\end{bmatrix}$

Multiply y + 2x = 5 by 2: 2y + 4x = 10

$\begin{bmatrix}2y-2x=-8\\ 2y+4x=10\end{bmatrix}$

subtracting the equations

$2y+4x=10$

$-$

$\underline{2y-2x=-8}$

$6x=18$

solve 6x = 18 for x

$6x=18$

Divide both sides by 6

$\frac{6x}{6}=\frac{18}{6}$

simplify

$x=3$

For 2y - 2x = -8 plug in x = 3

$2y-2\cdot \:3=-8$

$2y-6=-8$

Add 6 to both sides

$2y-6+6=-8+6$

Simplify

$2y=-2$

Divide both sides by 2

$\frac{2y}{2}=\frac{-2}{2}$

Simplify

$y=-1$

Therefore, the solution to the system of equations is:

(x, y) = (3, -1)

The graph is attached below.

8 0

2 years ago

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Ymorist [56]

I just answered this one

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2 years ago

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slega [8]

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2 years ago

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mihalych1998 [28]

Answer:

940

Step-by-step explanation:

188

940

--------------------------------------------------------

8 * 5 = 40

Carry the 4 to the next 8

8 * 5 = 40

Add the 4 to the 40

40 + 4 = 48

Carry the 4 to the 1

1 * 5 = 5

Add the 4

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*Hope this helps .^.*

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2 years ago

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AnnyKZ [126]

Answer:

Step-by-step explanation:

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