Which shows one way to determine the factors of 4x3 + x2 - 8x - 2 by grouping?

Mathematics

2 answers:

sergejj [24]3 years ago

8 0

Answer:

(x^2-2)(4x+1)

Step-by-step explanation:

4x^3 + x^2 - 8x - 2

Group:

(4x^3 + x^2)+( - 8x - 2)

Factor out as much as possible: (The GCF)

x^2(4x+1)-2(4x+1)

Regroup:

(x^2-2)(4x+1)

mr Goodwill [35]3 years ago

3 0

Answer:

(4x+1)(x²-2)

Step-by-step explanation:

one way to determine the factors of 4x^3 + x^2 - 8x - 2 by grouping:

x²(4x+1)-2(4x+1)

(4x+1)(x²-2)

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