Solve this plsss..........

Mathematics

1 answer:

kari74 [83]3 years ago

4 0

Answer:

xfbxcnfcvfxfhdfxbdfhsdxcbndf

Step-by-step explanation:

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Simplify -4x+2x2-x2+5-3x

Serga [27]

Answer:

9 - 7x - x²

Step-by-step explanation:

-4x+2x2-x²+5-3x = -4x-3x+2x2+5-x²

I arranged the like terms together so it is easier to do the calculations.

-4x-3x+2x2+5-x² = -7x+4+5-x²

Simplify.

-7x+4+5-x² = 9-7x-x²

3 0

2 years ago

Read 2 more answers

What is half of the fraction 3/4

schepotkina [342]

The half of 3/4 is 0.375, or 3/8. All you have to do is multiply 3/4 times 1/2.

5 0

3 years ago

An Epson inkjet printer ad advertises that the black ink cartridge will provide enough ink for an average of 245 pages. Assume t

Neko [114]

Answer:

35.2% probability that the sample mean will be 246 pages or more

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .