Answer:
The correct option is B.
Step-by-step explanation:
Given information: AB\parallel DCAB∥DC and BC\parallel ADBC∥AD .
Draw a diagonal AC.
In triangle BCA and DAC,
AC\cong ACAC≅AC (Reflexive Property of Equality)
\angle BAC\cong \angle DCA∠BAC≅∠DCA ( Alternate Interior Angles Theorem)
\angle BCA\cong \angle DAC∠BCA≅∠DAC ( Alternate Interior Angles Theorem)
The ASA (Angle-Side-Angle) postulate states that two triangles are congruent if two corresponding angles and the included side of are congruent.
By ASA postulate,
\triangle BCA\cong \triangle DAC△BCA≅△DAC
Therefore option B is correct
Answer:11 miles
Step-by-step explanation:
Answer:
b) 24
Step-by-step explanation:
We solve building the Venn's diagram of these sets.
We have that n(S) is the number of succesful students in a classroom.
n(F) is the number of freshmen student in that classroom.
We have that:

In which n(s) are those who are succeful but not freshmen and
are those who are succesful and freshmen.
By the same logic, we also have that:

The union is:

In which



So



So the correct answer is:
b) 24
I think it’s 5. I’m not sure
-16 + (-22) - 14
First, simplify your brackets. / Your problem should look like:
Second, subtract -16 - 22 - 14 to get -52. / Your problem should look like:

Answer:
-52