Y^4-4y^3+7y^2-6y-2y^3+8y^2-14y+12=
y^4-6y^3+15y^2-20y+12
or
y^3-4y^2+7y-6=y^3-4y^2+4y+3y-6=
y(y^2-4y+4)+3(y-2)=
y(y-2)^2+3(y-2)=(y-2)[y(y-2)+3]=(y-2)(y^2-2y+3)
(y^3-4y^2+7y-6)(y-2)=(y-2)^2(y^2-2y+3)
Nope - 320 millimetres = 32 centimetres. 3.2 metres is 320 centimetres, which is 3,200 millimetres
Of the 0 in 6.052 hope that helped
Answer:
(−2)×5<(−20)
Step-by-step explanation:
Evaluating the options given :
(−2)×5<(−20)
Open the bracket
- 10 < - 20 (false) ` This expression isn't true
(−2)×(−5)>(−25)
Open the bracket
10 > - 25 (true)
2×5>(−25)
Open the bracket
10 > - 25 (true)
2×(−5)<20
Open the bracket
- 10 < 20
A discrete variable is a variable which may take only certain discrete values; for example the number of people in a household is a discrete variable which may have the value 1, 2, 3, etc. but cannot have intermediate values such as 1.473 or 3.732.
Choice d) can be represented by a discrete probability distribution, the other choices cannot be so represented.
