I'm going to assume that there is something in A1 but the way you are describing the problem, you could just as easily write a constant in the formula you are using in cells E1 to E10 and F1 to F10
The trick is to refer to A1 as $A$1 which means that E1 to E10 isn't going to get creative and start looking for things in a1 to a10.
Here is an actual table made from what I think you mean
1 113 114
2 114 116
3 115 118
4 116 120
5 117 122
6 118 124
7 119 126
8 120 128
9 121 130
10 122 132
1 to 10 on the left is in column D
A1 contains 112
In column E the enteries from 1 to 10 simply take = $A$1 + d1
Column F uses $A$1 and adds 2*d to 112
Here is the chart shown in formula form.
1 =D1+$A$1 =$A$1 + 2*D1
2 =D2+$A$1 =$A$1 + 2*D2
3 =D3+$A$1 =$A$1 + 2*D3
4 =D4+$A$1 =$A$1 + 2*D4
5 =D5+$A$1 =$A$1 + 2*D5
6 =D6+$A$1 =$A$1 + 2*D6
7 =D7+$A$1 =$A$1 + 2*D7
8 =D8+$A$1 =$A$1 + 2*D8
9 =D9+$A$1 =$A$1 + 2*D9
10 =D10+$A$1 =$A$1 + 2*D10
Remember that 1 to 10 is in d1 to d10
Very simple:
As the sides that subtend the angle x are of equal lengths and are joined to form a triangle, we know the only other angle (the blank one) is going to also be 56° and since angles in a triangle always add up to 180°, we just have to do:
180 - (2 × 56) = 68°
First, let's calculate the triangles of the prism.
The area of a triangle is base times height, then divide by 2.
So:
(7*8)/2.
This would give us 28.
Also knowing that there are two triangles on the prism, we have to multiply 28 by 2. This would give us 56.
Now, for the rectangles, we have to find their areas.
The area of a rectangle is length times width. So this would give us:
8*16.
This equals 128.
Next, knowing that there are three rectangles, multiply 128 by three. This gives us 384.
Now, we jus have to add all the areas together:
384+56 = 440
So the prism's surface area is 440cm^2
Hope this helps. If you have any questions, please put them in the comments below.
Answer:
4 ≤ t ≤ 8
Step-by-step explanation:
Look at the graph and see if between the numbers whether the graph is going up or down.
The ball will just about pass because...
you need to find the percentage that the ball bounced back so you would need to do 6 ÷ 4.1 which is 0.683... Then to find the percentage you would multiply the answer by 100 so: 0.68333×100, which equals 68.333%. This means that the ball will pass the inspection as it scores between 68% and 75%.
