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Anastaziya [24]
3 years ago
9

If I get paid every Thursday and my check is roughly $100 and I put back $20 every week for a trip, how long will it take me to

get $2,000
Mathematics
2 answers:
Ksivusya [100]3 years ago
8 0
If you put away $20 every week,
it will take you

$2000 / $20 per week = 100 weeks

to save up the amount you want to have for the trip.

We don't care what day you get paid, or the amount of your paycheck.
zhenek [66]3 years ago
3 0
There are 52 weeks in a year ,so each week you put away $20 every week.It will take 100 weeks to reach $2,000.
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What is 212% in a decimal
4vir4ik [10]
The answer is:

212/100

=(200/100)+(12/100)

=2.00+0.12

=2.12
7 0
3 years ago
Read 2 more answers
20-{3+2[20÷4×5]}+16= -17 but I have to show how I got this.
aleksandr82 [10.1K]

20-{3+2(5*5)}+16

=20-{3+2*25}+16

=20-(3+50)+16

=20-53+16

=36-53

=-17

7 0
3 years ago
Which two functions are inverses of each other?
liraira [26]

Answer:

Option 3 - f(x)= 4x, g(x) = \frac{1}{4}x

Step-by-step explanation:

To find : Which two functions are inverses of each other?

Solution :

Two functions are inverse if f(g(x))=x=g(f(x))

Now, we find one by one

1) f(x)= x, g(x) = -x

f(g(x))=f(-x)=-x\neq x

Not true.

2) f(x)= 2x, g(x) = -\frac{1}{2}x

f(g(x))=f(-\frac{1}{2}x)=2\times(-\frac{1}{2}x)=-x\neq x

Not true.

3) f(x)= 4x, g(x) = \frac{1}{4}x

f(g(x))=f(\frac{1}{4}x)=4\times(\frac{1}{4}x)=x

g(f(x))=f(4x)=\frac{1}{4}\times 4x=x

i.e. f(g(x))=x=g(f(x)) is true.

So, These two functions are inverse of each other.

4) f(x)= -8x, g(x) =8x

f(g(x))=f(8x)=8\times(-8x)=-64x\neq x

Not true.

Therefore, Option 3 is correct.

6 0
3 years ago
Tyrice puts 4 cookies in each of 7 bags how many cookies did he put in each bag ?
eduard
He can't put one in each bag so we will have to go to the decimals 4 divided by 7 which equals to .5714
8 0
3 years ago
I don’t understand this help please
Elodia [21]

Answer:

  9

Step-by-step explanation:

The first simplification we can make is to replace 6^0 with 1.

The first rules of exponents we can apply are ...

  <em>(a·b)^c = a^c·b^c</em> . . . . . . similar to the distributive property

<em>   (a^b)^c = a^(b·c)</em>

This reduces your expression to ...

  (2^8\cdot 3^{-5})^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot 2^{28}=2^{8(-2)}\cdot 3^{-5(-2)}\cdot\dfrac{3^{-2(4)}}{2^{3(4)}}\cdot 2^{28}\\\\=2^{-16}\cdot 3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot 2^{28}

Now we can apply another two rules of exponents:

<em>   (a^b)(a^c) = a^(b+c)</em>

<em>   1/a^b = a^-b</em>

Using these, we have ...

  =2^{-16-12+28}\cdot 3^{10-8}\\\\=2^0\cdot 3^2\\\\=1\cdot 9=9

The value of the expression is 9.

3 0
3 years ago
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