Sorry I can't solve it.
Firstly, the equation is wrong. It is supposed to be <span>81 ≠ </span><span>30.25
Second of all, this is the best I got </span>81= <span><span>−<span>76 <span>(<span>cos<span>(r) </span></span></span></span></span>+ <span>106.25</span></span>
Answer:
R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Step-by-step explanation:
Squaring both sides of equation:
I^2 = (ER)^2/(R^2 + (WL)^2)
<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)
<=>(ER)^2 - (IR)^2 = (IWL)^2
<=> R^2(E^2 - I^2) = (IWL)^2
<=> R^2 = (IWL)^2/(E^2 - I^2)
<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Hope this helps!
Answer:
3 is greater than -4, but the line with slope -4 is steeper than the line with slope 3.
Step-by-step explanation:
3 is greater than -4, so strictly speaking, a slope of 3 is greater than a slope of -4.
On the other hand, the steepness of a line depends on the absolute value of the slope.
|3| = 3
|-4| = 4
Since 4 > 3, the line with slope -4 is steeper than the line with slope 3.
Answer: 3 is greater than -4, but the line with slope -4 is steeper than the line with slope 3.
26% = 26%/100%
26/100, 13/50
answer is 13/50
