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3 years ago

Q # ..19 anybody help me?

Mathematics

1 answer:

Goshia [24]3 years ago

3 0

The equation of the line with slope m and passing through the point $(x_0,y_0)$ is

$y-y_0=m(x-x_0).$

Since m=6 and the coordinates of the point are (8,3), then the equation is

$y-3=6(x-8).$

Answer: correct choice is B.

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What is the area of this polygon?

Cerrena [4.2K]

Answer:

<h2>39 units</h2>

Solution,

Total area=Area of ABCD+ Area of triangle ADE

 $(ab \times bc) + \frac{1}{2} \times ad \times ef \\ = (5 \times 6) + \frac{1}{2} \times 6 \times 3 \\ = 30 + 9 \\ = 39 \: {units}^{2}$ 

hope this helps...

Good luck on your assignment...

7 0

3 years ago

PERR AMD A PEERN2 SJE

Alla [95]

Answer:

3 peers

Step-by-step explanation:

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3 years ago

Read 2 more answers

The area of a rectangle is greater than or equal to 154 square centimeters. The width of the rectangle is 12 centimeters and the

soldier1979 [14.2K]

Answer:

x ≤ 12.83

(Any number under or equal to 12.8333...)

Step-by-step explanation:

154 ≥ 12x

12.833.... ≥ x

x ≤ 12.83

5 0

3 years ago

The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6

viktelen [127]

Answer:

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

The proportion of contracts involved between five and 10 inclusive bidders is 0.5.

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders No. contracts Relative frequency of contracts

2 6 6/102=0.0588

3 20 20/102=0.1961

4 24 24/102=0.2353

5 18 18/102=0.1765

6 13 13/102=0.1275

7 7 7/102=0.0686

8 5 5/102=0.049

9 6 6/102=0.0588

10 2 2/102=0.0196

11 1 1/102=0.0098

Total 102

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

We have to find proportion of contracts involved between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The proportion of contracts involved between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10= Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

8 0

3 years ago

It is given that y is directly proportional to x. When x = 3, y = 18. (a) Find the equation connecting x and y. (b) Hence, find

guapka [62]

Answer:

see explanation

Step-by-step explanation:

(a)

Given y is directly proportional to x then the equation relating them is

y = kx ← k is the constant of proportion

To find k use the condition when x = 3, y = 18 , then

18 = 3k ( divide both sides by 3 )

6 = k

y = 6x ← equation of proportion

(b)

(i)

when x = 12 , then

y = 6 × 12 = 72

(ii)

when y = 42

42 = 6x ( divide both sides by 6 )

7 = x

8 0

3 years ago