Question

Indicate in standard form the equation of the line through the given points. k(6 4) l(-6 4) with a slope of m=5

Answer 1

Set up a point-slope form equation:
y-y1 = m(x-x1)
y-4 = 5(x-6)
y-4 = 5x -30

Standard form is Ax + By = C

bring x & y over to the same side.

y-4 = 5x-30
-5x + y = -26

Hope this helps

Answer 2

By definition, the generic equation of the line in its point-slope form is given by:

$y-yo = m (x-xo)$

Where,

m: slope of the line

(xo, yo): pair ordered by where the line passes.

The slope of the line is:

$m = 5$

By choosing an ordered pair we have:

$(xo, yo) = (6, 4)$

Substituting values we have:

$y-4 = 5 (x-6)$

Rewriting the equation in its standard form we have:

$y-4 = 5x-30\\y = 5x-30 + 4\\y = 5x-26$

Answer:

The equation of the line in standard form is:

$y = 5x-26$