It would be two and ninety four hundredths
Let
x = larger integer
y = smaller integer
The two integers (x and y) have a sum of 42 which means they add to 42
x+y = 42
solve for y to get
y = 42-x
simply by subtracting x from both sides
---------------------------------------------------
The two integers have a difference of 22. This translates to "subtract the values and the result will be 22", i.e.,
x-y = 22
Plug in y = 42-x. Solve for x
x-y = 22
x-(y) = 22
x - (42-x) = 22
x - 42 + x = 22
2x - 42 = 22
2x - 42+42 = 22+42
2x = 64
2x/2 = 64/2
x = 32
If x = 32, then y is...
y = 42-x
y = 42-32
y = 10
Therefore,
x = 32
y = 10
The final answer is 10
Answer: 6x + 6
Step-by-step explanation:x = the number 5x + (x + 6) {five times the number added to the sum of the number and six} = 5x + x + 6 {took out parentheses}
For this case we have to by definition, if "y" varies directly with "x" it is represented as:
Where:
k: It is the constant of proportionality
We have to:
We clear the variable "y":
Thus, the constant of proportionality is:
Answer:
Answer:
-21
Step-by-step explanation:
1-2+4-8+16-32
=-21
