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3 years ago

Please help em with this one plz

Mathematics

1 answer:

abruzzese [7]3 years ago

4 0

The correct answer is y=6x^(2)-1

Multiple 'm' in y=mx+b By 8
8(3/4)= 24/4= 6

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1.6x=1.28<br> help me solve this

bogdanovich [222]

Answer:

Step-by-step explanation:

Sure! So, we need to divide by 1.6 on each side to isolate the x.

1.6x / 1.6 is just x. We need to divide by the same on the other side too!

1.28 / 1.6 is 0.8.

So x = 0.8

7 0

2 years ago

Caleb drives for 3.5 hours at 65 miles per hour. How far does he travel? do not round your answer

Allushta [10]

Answer:

227.5

Step-by-step explanation: You have to multiply 3.5 times 65

Hope this helps!!!

6 0

3 years ago

The volume of a cube depends on the length of its sides. This can be written in function notation as v(s). V(4)=64

iren2701 [21]

Answer:

V(s) = s³

Step-by-step explanation:

4³ = 64

4 0

3 years ago

Read 2 more answers

Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line.? y = 2 + se

sertanlavr [38]

Answer:

The volume of the solid is: $\mathbf{V = \pi [ \dfrac{8 \pi}{3} - 2\sqrt{3}]}$

Step-by-step explanation:

GIven that :

$y = 2 + sec \ x , -\dfrac{\pi}{3} \leq x \leq \dfrac{\pi}{3} \\ \\ y = 4\\ \\ about \ y \ = 2$

This implies that the distance between the x-axis and the axis of the rotation = 2 units

The distance between the x-axis and the inner ring is r = (2+sec x) -2

Let R be the outer radius and r be the inner radius

By integration; the volume of the of the solid can be calculated as follows:

$V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [(4-2)^2 - (2+ sec \ x -2)^2]dx \\ \\ \\ V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [(2)^2 - (sec \ x )^2]dx \\ \\ \\ V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [4 - sec^2 \ x ]dx$

$V = \pi [4x - tan \ x]^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} \\ \\ \\ V = \pi [4(\dfrac{\pi}{3}) - tan (\dfrac{\pi}{3}) - 4(-\dfrac{\pi}{3})+ tan (-\dfrac{\pi}{3})] \\ \\ \\ V = \pi [4(\dfrac{\pi}{3}) - tan (\dfrac{\pi}{3}) + 4(\dfrac{\pi}{3})- tan (\dfrac{\pi}{3})] \\ \\ \\ V = \pi [8(\dfrac{\pi}{3}) - 2 \ tan (\dfrac{\pi}{3}) ]$

$\mathbf{V = \pi [ \dfrac{8 \pi}{3} - 2\sqrt{3}]}$

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3 years ago

How did the absent-minded proffesor burn his ear

Ksenya-84 [330]

I believe he was ironing when the phone rang.

3 0

3 years ago