A data set lists weights (lb) of plastic discarded by households. The highest weight is 5.24 lb, the mean of all of the weight
1 answer:
Answer:
a) 3.308 lb
b) That difference is 2.91 standard deviations.
c)
d) We have that , so the weight of 5.24lb is significantly high.
Step-by-step explanation:
The z-score formula is given by:
In which: X is the weight we are going to find the z-score of, is the mean of all the weights and
is the standard deviation of all the weights.
The problems gives these following informations:
The highest weight is 5.24 lb
The mean of all the weights is 1.932 lb
The standard deviation of all the weights is 1.135 lb
a. What is the difference between the weight of 5.24 lb and the mean of the weights?
b. How many standard deviations is that [the difference found in part (a)]?
The difference found in (a) is 3.308lb.
This can be calculated by a simple rule of three.
1 standard deviation - 1.135lb
x standard deviations - 3.308lb
That difference is 2.91 standard deviations.
c. Convert the weight of 5.24 lb to a z score.
We have that:
and
. So:
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Answer:
A, D, E are true
Step-by-step explanation:
You have to complete the square to prove A. Do this by first setting the function equal to 0, then moving the 5 to the other side.
Now we can complete the square. Take half the linear term, square it, and add it to both sides. Our linear term is 8 (from the -8x). Half of 8 is 4, and 4 squared is 16. So we add 16 to both sides.
We will do the addition on the right, no big deal. On the left, however, what we have done in the process of completing the square is to create a perfect square binomial, which gives us the h coordinate of the vertex. We will rewrite with that perfect square on the left and the addition done on the right,
Now we will move the 11 back over, which gives us the k coordinate of the vertex.
From this you can see that A is correct.
Also we can see that the vertex of this parabola is (4, -11), which is why B is NOT correct.
The axis of symmetry is also found in the h value. This is, by definition, a positive x-squared parabola (opens upwards), so its axis of symmetry will be an "x = " equation. In the case of this type of parabola, that "x = " will always be equal to the h value. So the axis of symmetry is
x = 4, which is why C is NOT correct, either.
We can find the y-intercept of the function by going back to the standard form of the parabola (NOT the vertex form we found by completing the square) and sub in a 0 for x. When we do that, and then solve for y, we find that when x = 0, y = 5. So the y-intercept is (0, 5).
From this you can see that D is also correct.
To determine if the parabola has real solutions (meaning it will go through the x-axis twice), you can plug it into the quadratic formula to find these values of x. I just plugged the formula into my graphing calculator and graphed it to see that it did, indeed, go through the x-axis twice. Just so you know, the values of x where the function go through are (.6833752, 0) and (7.3166248, 0). That's why you need the quadratic formula to find these values.