96271723r1 if u are going 60 miles per hour
C is the answer to your question
Answer:
A
Step-by-step explanation:
-x + 2y = 8
5x + 2y = -4
+ x. -2y. -8
6x = -12
÷6. ÷6
x = -2
5(-2) + 2y = -4
-10 + 2y = -4
+10. +10
2y = 6
÷2. ÷2
y = 3
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
