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4 years ago

A right triangle has legs measuring 20 in. and 28 in.

Mathematics

2 answers:

lora16 [44]4 years ago

6 0

C2 = a2 + b2
c2 = 20^2 + 28^2
c2 = 400 + 784
c2 = 1184
c = 34.4

statuscvo [17]4 years ago

3 0

Answer: 34.4 inch

Step-by-step explanation:

We know that the Pythagoras theorem says that in a right triangle the square of hypotenuse is equal to the sum of the squares of the legs of the triangle.

Let H be the hypotenuse.

Therefore for the given right triangle , we have

$H^2=20^+28^2\\\\\Rightarrow H^2=400+784\\\\\Rightarrow H^2=1184\\\\\Rightarrow H=\sqrt{1184}\\\\\Rightarrow H=34.4093010682\approx34.4\ in$

Thus, the length of the hypotenuse = 34.4 inch

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_____ divided by 2/3=3/4<br>

Lina20 [59]

Answer:

$\frac{1}{2}$

Step-by-step explanation:

Multiply the quotient $\frac{3}{4}$ by the divisor $\frac{2}{3}$ for the dividend, that is

$\frac{3}{4}$ × $\frac{2}{3}$

Cancel the 3 on the numerator/ denominator

= $\frac{1}{4}$ × $\frac{2}{1}$ = $\frac{2}{4}$ = $\frac{1}{2}$

4 0

3 years ago

How do you find the solution of this proportion?<br> 4/9 = m2-1/54 <br> m2 is m to the power of 2

elena-14-01-66 [18.8K]

Answer:

±5sqrt(6)/6 = m

Step-by-step explanation:

4/9 = m^2-1/54

Add 1/54 to both sides

4/9+ 1/54 = m^2-1/54 +1/54

4/9+ 1/54 = m^2

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4/9 *6/6 + 1/54 = m^2

24/54 + 1/54 = m^2

25/54 = m^2

Take the square root of each side

±sqrt(25/54) = sqrt(m^2)

±sqrt(25/54) = m

±sqrt(25)/sqrt(54) = m

±sqrt(25)/sqrt(9)sqrt(6) = m

±5/3sqrt(6) = m

±5/3sqrt(6) *sqrt(6)/sqrt(6) = m

±5sqrt(6)/3*6 = m

±5sqrt(6)/6 = m

8 0

3 years ago

What is this im confused it the qestion on math its p×13= -52

Vesna [10]

The question is asking you to solve for p. For your question, p = -4. 13 * -4 = -52 so -4 is the correct answer.

Hope this helps! :)

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3 years ago

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AnnZ [28]

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4 years ago

Fred flips a coin, spins the spinner, and rolls a standard number cube. Find the probability that the coin will show tails, the

Inessa05 [86]

Answer:

The probability that the coin will show tails, the spinner will land on yellow or green (out of yellow, green, blue), and the cube will show a three is $\frac{4}{3}$

Step-by-step explanation:

Given : Fred flips a coin, spins the spinner, and rolls a standard number cube.

To find : The probability that the coin will show tails, the spinner will land on yellow or green (out of yellow, green, blue), and the cube will show a three ?

Solution :

First we find probability one by one,

1) Flips a coin - Head, Tail

Total number of outcome = 2

Favorable outcome (getting a tail) = 1

Probability that the coin will show tails is $P(T)=\frac{1}{2}$

2) Spins the spinner - yellow, green, blue

Total number of outcome = 3

Favorable outcome (land on yellow or green) = 2

Probability that the spinner will land on yellow or green $P(S)=\frac{2}{3}$

3) Rolls a standard number cube - 1,2,3,4,5,6

Total number of outcome = 6

Favorable outcome (show a three) = 1

Probability that the cube will show a three $P(C)=\frac{1}{6}$

The probability that the coin will show tails, the spinner will land on yellow or green (out of yellow, green, blue), and the cube will show a three is

$P=P(T)+P(S)+P(C)$

$P=\frac{1}{2}+\frac{2}{3}+\frac{1}{6}$

$P=\frac{3+4+1}{6}$

$P=\frac{8}{6}$

$P=\frac{4}{3}$

Therefore, The probability that the coin will show tails, the spinner will land on yellow or green (out of yellow, green, blue), and the cube will show a three is $\frac{4}{3}$

5 0

3 years ago