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JulijaS [17]
3 years ago
6

What is this im confused it the qestion on math its p×13= -52

Mathematics
2 answers:
Vesna [10]3 years ago
7 0

The question is asking you to solve for p. For your question, p = -4. 13 * -4 = -52 so -4 is the correct answer.

Hope this helps! :)

Shtirlitz [24]3 years ago
3 0

Answer:

Divide 13 on both sides

p=-4

Hope I helped!

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Keith_Richards [23]

Answer:

b-d-e

Step-by-step explanation:

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7 0
3 years ago
What is the value of 4p-2, when p=8
ohaa [14]
4p - 2  when p=8

(4 x 8) - 2
32 - 2
30

answer: 30
hope it helped :)
7 0
3 years ago
Read 2 more answers
Please Help Quick ASAp Hurry
alexgriva [62]

Answer:

B. 5070π in³

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Geometry </u>

Volume of a Cylinder Formula: V = πr²h

  • <em>r</em> is radius
  • <em>h</em> is height

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

<em>r</em> = 13 in

<em>h</em> = 30 in

<u>Step 2: Find Volume</u>

  1. Substitute in variables [Volume of a Cylinder Formula]:                                V = π(13 in)²(30 in)
  2. Evaluate exponents:                                                                                         V = π(169 in²)(30 in)
  3. Multiply:                                                                                                             V = 5070π in³
8 0
3 years ago
Read 2 more answers
BD−→− bisects ∠ABC such that m∠ABD = (4x−5)∘ and m∠DBC = (3x+2)∘.
Rzqust [24]

Answer:

\angle ABC=(46)^{\circ}

Step-by-step explanation:

Given: BD bisects \angle ABC

\angle ABD=(4x-5)^{\circ}\\\angle DBC=(3x+2)^{\circ}

To find: \angle ABC

Solution:

A bisector of an angle divides it into angles of equal measures.

As BD bisects \angle ABC, \angle ABD=\angle DBC

Put \angle ABD=(4x-5)^{\circ}\,,\,\angle DBC=(3x+2)^{\circ}

\angle ABD=\angle DBC\\(4x-5)^{\circ}=(3x+2)^{\circ}\\4x-3x=2+5\\x=7^{\circ}

So,

\angle ABD=(4x-5)^{\circ}=(4(7)-5)^{\circ}=(28-5)^{\circ}=(23)^{\circ}\\\angle DBC=(3x+2)^{\circ}=(3(7)+2)^{\circ}=(21+2)^{\circ}=(23)^{\circ}

\angle ABC=\angle ABD+\angle DBC\\=(23)^{\circ}+(23)^{\circ}\\=(46)^{\circ}

3 0
3 years ago
Find the product:<br><br> (5/3)(2/3)(2/1)
vampirchik [111]

Answer:

20/9

Step-by-step explanation:

Hope this helps!

6 0
3 years ago
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