Question

A car sells for \$5000$5000dollar sign, 5000 and loses \dfrac{1}{10}

Answer 1

Answer:

The function that gives the car's value is

$V(t)=5000(1-\frac1{10})^t$

where V(t) is in dollar and t is number of years after it sold.

Step-by-step explanation:

Given that,

A car sells for $5000 and losses $\frac1{10}$ of its value each year.

The value of car will loss after 1 year is

$=\ 5000 \times \frac1{10}$

The price of the car after 1 year is

$=\ (5000-5000\times \frac 1{10})$

$=\ \{5000(1-\frac1{10})\}$

$=\ \{5000(1-\frac1{10})^1\}$

The value car will loss in 2 year is

$=\ \{5000(1-\frac1{10})\times \frac1{10}\}$

After 2nd year the car will be

$=\ \{5000(1-\frac1{10})\}-\{5000(1-\frac1{10})\times \frac1{10}\}$

$=\ \{5000(1-\frac1{10})\}(1-\frac1{10})$

$=\ \{5000(1-\frac1{10})^2\}$

Similarly the value of car after t years is

$=\ \{5000(1-\frac1{10})^t\}$

The function that gives the car's value is

$V(t)=5000(1-\frac1{10})^t$

where V(t) is in dollar and t is number of years after it sold.