Perimeter of triangle ABC is 20 units.
Solution:
The image for reference is attached below.
Given AE = 2, BD = 5 and CF = 3
Two tangents drawn from an external point to a circle are equal in length.
AD = AE, BF = BD and CE = CF
Therefore, AD = 2, BF = 5 and CE = 3
Perimeter of the triangle = sum of the three sides
Perimeter of triangle ABC = AB + BC + CA
= AD + BD + BF + CF + CE + AE
= 2 + 5 + 5 + 3 + 3 + 2
= 20
Hence, perimeter of triangle ABC is 20 units.
Answer: 47 degrees
Step-by-step explanation:
7x-9=4x+15 because of the vertical angle rule
7x-9=4x+15
3x=24
x= 8
So the angle 7(8)-9 = 47°
The y-coordinate of the solution is 11.
Both equations have y isolated. We will use substitution for this system:
5x-9=x²-3x+7
We want to gather all of the variables on one side, so we will subtract 5x from each side:
5x-9-5x=x²-3x+7-5x
-9=x²-8x+7
We want the equation to be equal to 0 to solve it, so we will add 9 to both sides:
-9+9=x²-8x+7+9
0=x²-8x+16
This is easy to factor; factors of 16 that sum to -8 are -4 and -4:
0=(x-4)(x-4)
Since these are the same factor, we solve it to get our answer:
x-4=0
x-4+4=0+4
x=4
Substitute this into the first, linear, equation:
y=5(4)-9=20-9=11
Answer:
14 teenagers attended the game.
Step-by-step explanation:
