Triangle ABC has vertices A (1,1) B (7,1) C (4,9) (A)Find the perimeter of triangle ABC. (B) Find the area of triangle ABC
1 answer:
9514 1404 393
Answer:
- perimeter = 6+2√73 ≈ 23.09 units
- area = 24 units²
Step-by-step explanation:
It can help to draw a figure.
The altitude of this isosceles triangle is 8 units, and it splits the base into equal lengths of 3 units. Using the Pythagorean theorem, we find the length of a side to be ...
BC = AC = √(3² +8²) = √73
The perimeter is the sum of the lengths of those two sides and the base:
P = 2(√73) +6 ≈ 23.088 . . . units
The area is given by the formula ...
A = 1/2bh
A = (1/2)(6 units)(8 untis) = 24 units²
__
The perimeter is 6+2√73 ≈ 23.09 units.
The area is 24 units².
You might be interested in
Here you go, hope I helped.
