A group of 625 students has a mean age of 15.8 years with a standard deviation of 0.6 years. The ages are normally distributed.
How many students are younger than 16.2 years? Express answer to the nearest student.
1 answer:
16.2-15.8/0.6=0.6667. Use normalcdf() to find the percentage from -999 to 0.6777 which is 0.7476*625=467
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83-63=20
So your answer is 20
62.5%
5/8 = 0.625 then multiply by 100% to get in terms of percent of 62.5%
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Step-by-step explanation: