Question

Can you guys plzzz help. This is precalc. I’m a senior

Answer 1

Answer:

See below.

Step-by-step explanation:

Answer 2

Answer:

1. $\left[\begin{array}{ccc}-3&-8\\6&3\\2&8\end{array}\right]$  , 2.  $\left[\begin{array}{ccc}-8&-4&21\\-8&6&7\end{array}\right]$

Step-by-step explanation

1. $\left[\begin{array}{ccc}4&-3\\0&-1\\5&8\end{array}\right] - \left[\begin{array}{ccc}7&5\\-6&-4\\3&0\end{array}\right]$

To solve just that each in the first matrix block and substract     with their equivalent in the second matrix block.  

For example 4 -7 = -3, -3-5= -8

$\left[\begin{array}{ccc}-3&-8\\6&3\\2&8\end{array}\right]$  

2. $-2\left[\begin{array}{ccc}10&2&-3\\1&6&-5\end{array}\right] + 3\left[\begin{array}{ccc}4&0&5\\-2&6&-1\end{array}\right]$

Multiply first block with -2 and the second block by 3

$\left[\begin{array}{ccc}-20&-4&6\\-2&-12&10\end{array}\right] + \left[\begin{array}{ccc}12&0&15\\-6&18&-3\end{array}\right]$

Add just the same as question 1

$\left[\begin{array}{ccc}-8&-4&21\\-8&6&7\end{array}\right]$