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STatiana [176]
3 years ago
11

Can you guys plzzz help. This is precalc. I’m a senior

Mathematics
2 answers:
Dafna1 [17]3 years ago
8 0

Answer:

See below.

Step-by-step explanation:

Eddi Din [679]3 years ago
3 0

Answer:

1. \left[\begin{array}{ccc}-3&-8\\6&3\\2&8\end{array}\right]  , 2.  \left[\begin{array}{ccc}-8&-4&21\\-8&6&7\end{array}\right]

Step-by-step explanation

1. \left[\begin{array}{ccc}4&-3\\0&-1\\5&8\end{array}\right] - \left[\begin{array}{ccc}7&5\\-6&-4\\3&0\end{array}\right]

To solve just that each in the first matrix block and substract     with their equivalent in the second matrix block.  

For example 4 -7 = -3, -3-5= -8

\left[\begin{array}{ccc}-3&-8\\6&3\\2&8\end{array}\right]  

2. -2\left[\begin{array}{ccc}10&2&-3\\1&6&-5\end{array}\right]  + 3\left[\begin{array}{ccc}4&0&5\\-2&6&-1\end{array}\right]

Multiply first block with -2 and the second block by 3

\left[\begin{array}{ccc}-20&-4&6\\-2&-12&10\end{array}\right] + \left[\begin{array}{ccc}12&0&15\\-6&18&-3\end{array}\right]

Add just the same as question 1

\left[\begin{array}{ccc}-8&-4&21\\-8&6&7\end{array}\right]

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