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Tasya [4]
3 years ago
14

Two friends, 7 miles apart, start walking toward each other, and they meet in an hour. If one boy walks 1 mile farther in an hou

r than the other boy, how fast does each walk?
Mathematics
2 answers:
Alexeev081 [22]3 years ago
7 0

Answer:

The answer is 3 miles and 4 miles.

Xelga [282]3 years ago
3 0
So lets say the distance one boy travels is 'x', you can set up an equation like this:
x + x + 1 = 7
2x +1 = 7
2x = 6
x = 3
So one boy walks 3 miles in one hour, and the other walks 4 miles in one hour.
Therefore, their speeds are 3 miles per hour and 4 miles per hour respectively.

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Answer:

<u>=-26.7</u>

Step-by-step explanation:

=-13.9+(-12.8)

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<u>=-26.7</u>

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Let AA and BB be events such that P(A∩B)=1/73P(A∩B)=1/73, P(A~)=68/73P(A~)=68/73, P(B)=21/73P(B)=21/73. What is the probability
krok68 [10]

Answer:

P(A \cup B) = \frac{5}{73} +\frac{21}{73} -\frac{1}{73}=\frac{25}{73}

Step-by-step explanation:

Let A and B events. We have defined the probabilities for some events:

P(A') =\frac{68}{73} , P(B) =\frac{21}{73} , P(A \cap B) =\frac{1}{73}

Where A' represent the complement for the event A

The complement rule is a theorem that provides a connection between the probability of an event and the probability of the complement of the event. Lat A the event of interest and A' the complement. The rule is defined by: P(A)+P(A') =1

So for this case we can solve for P(A) like this:

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And now we can find P(A \cup B) using the total probability rul given by:

P(A \cup B) = P(A)+P(B) -P(A \cap B)

And if we replace the values given we got:

P(A \cup B) = \frac{5}{73} +\frac{21}{73} -\frac{1}{73}=\frac{25}{73}

And that would be the final answer.

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Sedbober [7]

Hello from MrBillDoesMath!

Answer:

12 m n^2

Discussion:

3m * 4 * n * n  =                       => 3* 4 = 12

12 m * n * n                              => as n*n = n^2

12 m n^2

Thank you,

MrB

7 0
3 years ago
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