If f(x) is a continuous function defined for all real numbers, f(–1) = 1, f(–5) = –10, and f(x) = 0 for one and only one value o
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Since you know the value of "x", you can plug in the value for "x" in the equation.
[When an exponent is negative, you move it to the other side of the fraction to make the exponent positive.]
For example:
or
or y³
x = -2
f(x) = 9x + 7
f(-2) = 9(-2) + 7 = -18 + 7 = -11
(idk if you should have it as a decimal or a fraction)
x = -1
f(x) = 9x + 7
f(-1) = 9(-1) + 7 = -9 + 7 = -2
x = 0
f(x) = 9x + 7
f(0) = 9(0) + 7 = 7
x = 1
f(x) = 9x + 7
f(1) = 9(1) + 7 = 9 + 7 = 16
x = 2
f(x) = 9x + 7
f(2) = 9(2) + 7 = 18 + 7 = 25
You need to determine the solution of f(x) = g(x)
Since you know f(x) = 9x + 7 and , you can plug in (9x + 7) for f(x), and (
) into g(x)
f(x) = g(x)
You can plug in each value of x into the equation
Your answer is x = 2 because when you plug in 2 for x in the equation, you get 25 = 25