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maria [59]
4 years ago
11

Which equation could represent the relationship shown in the scatter plot? y=−3x−2

Mathematics
2 answers:
madreJ [45]4 years ago
6 0

Answer:  the answer is y=-34x+10

Step-by-step explanation:

Orlov [11]4 years ago
3 0

Answer:

Y=-3/4x + 10

Step-by-step explanation:


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Express in the form 1:n give n as a decimal 8:6
photoshop1234 [79]

Answer: 8.6:8.6

Explanation:

1:n is the form you want.

n is 8.6. change the n value so it is 1:8.6

1 is 1 times bigger than 8.6

8.6 times 1 is 8.6

so you've got 8.6:8.6

your welcome, i hope this helps

3 0
3 years ago
Find the missing angle.
Lina20 [59]

Answer:

0.76 or 0.8

Step-by-step explanation:

4 0
3 years ago
The science club sold 24 t-shirts last week and 18 T-shirts this week. What is the percentage of decrease in the number of T-shi
MAVERICK [17]

Answer:

D) 75%

Step-by-step explanation:

75% of 24 = 0.75 x 24 = 18

6 0
3 years ago
Give a rule of the piecewise-defined function.
nataly862011 [7]

The equation of the piecewise function is f(x) = \left[\begin{array}{ccc}3&x \le -1\\-1&x > 2\end{array}\right

<h3>The piecewise function</h3>

On the graph, we have:

  • y = 3 for all x values not more than -1
  • y = -1 for all values greater than 2

Hence, the piecewise function is:

f(x) = \left[\begin{array}{ccc}3&x \le -1\\-1&x > 2\end{array}\right

<h3>The domain of the function</h3>

This is the set of input values

In (a), we have:

x ≤ -1 and x > 2

Hence, the domain is (∞, 3] u (2, ∞)

<h3>The range of the function</h3>

This is the set of output values

In (a), we have:

f(x) = 3 and f(x) -1

Hence, the range is [3] u (-1)

Read more about piecewise function at:

brainly.com/question/18859540

#SPJ1

5 0
2 years ago
Evaluate the integral by interpreting it in terms of areas Draw a picture of the region the integral
denis23 [38]

Answer:

Step-by-step explanation:

The picture is below of how to separate this into 2 different regions, which you have to because it's not continuous over the whole function. It "breaks" at x = 2. So the way to separate this is to take the integral from x = 0 to x = 2 and then add it to the integral for x = 2 to x = 3. In order to integrate each one of those "parts" of that absolute value function we have to determine the equation for each line that makes up that part.

For the integral from [0, 2], the equation of the line is -3x + 6;

For the integral from [2, 3], the equation of the line is 3x - 6.

We integrate then:

\int\limits^2_0 {-3x+6} \, dx+\int\limits^3_2 {3x-6} \, dx    and

-\frac{3x^2}{2}+6x\left \} {{2} \atop {0}} \right.  +\frac{3x^2}{2}-6x\left \} {{3} \atop {2}} \right.  sorry for the odd representation; that's as good as it gets here!

Using the First Fundamental Theorem of Calculus, we get:

(6 - 0) + (-4.5 - (-6)) = 6 + 1.5 = 7.5

5 0
3 years ago
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