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Brums [2.3K]
3 years ago
7

Compare using <, >, or =. 1/2 ___ 5/10 < > =

Mathematics
1 answer:
k0ka [10]3 years ago
3 0
\frac{1}{2} =  0.5
\frac{5}{10}  = 0.5

∴  \frac{1}{5}  =   \frac{5}{10}
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Using the following image, find GH given HI = 1 and GI =<br> = 9.
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8

Step-by-step explanation:

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Which situation is modeled by the graph?
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Well i know by looking for sure it is not D or C. so that eliminates 2 answers which leaves A and B. i believe the best answer for this is A. if i am wrong please let me know, if i am correct then let me know swell. hope this helps.
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Tell whether (1,6) is a solution of y = x + 7
andrezito [222]

Answer:

no it is not a solution.READ THE WHOLE EXPLANATION! IT WILL HELP WITH THE OTHER PROBLEMS!!!!

Step-by-step explanation:

when something like (1,6) is written consider it as (x,y). in this case, 1 is considered as x, and 6 is considered as y. if you substitute these number for x and x and y, (x =1 and y =6), you'll see that the equation will go from y=x +7, to 6=1+7. Which is not true.

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2 years ago
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A used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a l
Daniel [21]

Answer:

C. 1000 loss.

Step-by-step explanation:

Let x represent purchase price of each car.

We have been given that a used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a loss of 20 percent of the dealer's purchase price for that car.

We can represent the car that dealer sold with 25% profit to find purchase price as:

x+0.25x=20,000

1.25x=20,000

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x=16,000

Therefore, the purchase price of 1st car was $16,000.

We can represent the car that dealer sold with 20% loss to find purchase price as:

x-0.20x=20,000

0.80x=20,000

\frac{0.80x}{0.80}=\frac{20,000}{0.80}

x=25,000

Therefore, the purchase price of 2nd car was $25,000.

The total purchase price of both cars would be 16,000+25,000=41,000

The total sale price of both cars 20,000+20,000=40,000.

We can see that the sale price of both car is less than purchase price by $1000, so the dealer got a loss of $1000.

Therefore, the dealer's total loss, in dollars, for the two transactions combined was 1000 and option C is the correct choice.

4 0
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What do you need help clarifying? Did you want to go over the questions you missed? (:

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