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4 years ago

n an oxidation-reduction reaction, oxidation is what happens when a reactant . Reduction occurs when a reactant in the reaction.

Chemistry

2 answers:

Tasya [4]4 years ago

6 0

Answer:

Oxidation occurs when a reactant loses electrons during the reaction. Reduction occurs when a reactant gains electrons during the reaction. This often occurs when metals are reacted with acid.

erma4kov [3.2K]4 years ago

6 0

Answer : Oxidation reaction occurs when a reactant losses electrons in the reaction.

Reduction reaction occurs when a reactant gains electrons in the reaction.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. That means, the loss of electrons takes place.

Or we can say that, oxidation reaction occurs when a reactant losses electrons in the reaction.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. That means, the gain of electrons takes place.

Or we can say that, reduction reaction occurs when a reactant gains electrons in the reaction.

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3 years ago

Which of the following statements correctly explains how latitude affects temperature?

dusya [7]

Answer:

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2 years ago

The mass of an unidentified metal sphere is 133 grams. Students determine the

Rainbow [258]

Given the data from the question, the identity of the unknown metal having a of mass 133 g is Cobalt

<h3>What is density? </h3>

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

<h3>How to determine the density </h3>

Mass = 133 g
Volume of water = 25 mL
Volume of water + metal = 40 mL
Vol of metal = 40 – 25 = 15 mL

Density =?

Density = mass / volume

Density = 133 / 15

Density = 8.86 g/mL

Comparing the density of the unknown metal (i.e 8.86 g/mL) with those given in the chart in the question above, we can conclude that the unknown metal is Cobalt

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2 years ago

What are the various forms of energy?

Fantom [35]

Science has classified energy into two main forms: kinetic energy and potential energy. In addition, potential energy takes several forms of its own. Kinetic energy is defined as the energy of a moving object.

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3 years ago

Read 2 more answers

A sample of sodium sulfite has a mass of 2.80 g.

Gnom [1K]

<u>Answer:</u>

<u>For a:</u> The number of sodium ions in given amount of sodium sulfite are $2.65\times 10^{22}$

<u>For b:</u> The number of sulfite ions in given amount of sodium sulfite are $1.325\times 10^{22}$

<u>For c:</u> The mass of one formula unit of sodium ions is $2.09\times 10^{-22}$ grams

<u>Explanation:</u>

The chemical formula of sodium sulfite is $Na_2SO_3$ . It is formed by the combination of 2 sodium $(Na^+)$ ions and 1 sulfite $(SO_3^{2-})$ ions

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of sodium sulfite = 2.80 g

Molar mass of sodium sulfite = 126 g/mol

Putting values in above equation, we get:

$\text{Moles of sodium sulfite}=\frac{2.80g}{126g/mol}=0.022mol$

<u>For a:</u>

Moles of sodium ions in sodium sulfite = (2 × 0.022) moles

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of particles

So, 0.022 moles of sodium sulfite will contain = $(2\times 0.022\times 6.022\times 10^{23})=2.65\times 10^{22}$ number of sodium ions

Hence, the number of sodium ions in given amount of sodium sulfite are $2.65\times 10^{22}$

<u>For b:</u>

Moles of sulfite ions in sodium sulfite = (1 × 0.022) moles

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of particles

So, 0.022 moles of sodium sulfite will contain = $(1\times 0.022\times 6.022\times 10^{23})=1.325\times 10^{22}$ number of sulfite ions

Hence, the number of sulfite ions in given amount of sodium sulfite are $1.325\times 10^{22}$

<u>For c:</u>

Molar mass of sodium sulfite = 126 g/mol

According to mole concept:

$6.022\times 10^{23}$ number of formula units are present in 1 mole of a compound

Or, $6.022\times 10^{23}$ number of formula units of sodium sulfite have a mass of 126 grams

So, 1 formula unit of sodium sulfite will have a mass of = $\frac{126}{6.022\times 10^{23}}\times 1=2.09\times 10^{-22}g$

Hence, the mass of one formula unit of sodium ions is $2.09\times 10^{-22}$ grams

7 0

3 years ago