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3 years ago

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A container holds 800 mL of a gas at 25.0 C and 745 tore. What will be the volume of the gas of the pressure is increased to 790

torr and the temperature remains constant at 25.0C

1 answer:

olga_2 [115]3 years ago

8 0

Answer: 75 C

Explanation:

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The reaction of iron (III) oxide with carbon monoxide produces iron and carbon dioxide.

True [87]

Answer:

21g

Explanation:

no.ofmol fe2o3=39.5/(56×2+16×3)=0.25mol

from equation 1mole fe2o3 react with 3mole co

so,0.25mol fe2o3 react with 0.75mol co

mass of co=0.75×(12+16)=21g

8 0

2 years ago

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If it takes 22974 J to heat 96.5 g of a substance from 13.46°C to 73.86 °C, what is the specific heat of the substance?

yulyashka [42]

The specific heat capacity, C, of the substance is 3.94 $\frac{J}{g-^oC}$ . To raise one gram of a substance by one degree Celsius, a specific amount of heat must be absorbed. This is called the specific heat of the substance. The higher the specific heat of a substance, the more energy is needed to increase its temperature and vice versa.

<u>Further Explanation: </u>

The specific heat capacity, C, of a substance is related to the amount of substance and the temperature change using the following equation

$q \ = \ mC(T_{f}-T_{i})$

where

q = amount of heat absorbed (usually in J)

m = amount of substance (in g)

C = specific heat capacity (in $\frac{J}{g-^oC}$ )

T(f) = final temperature

T(i) = initial temperature.

To answer the problem, we sort the given information:

q = 22974 J (5 significan figures)

m = 96.5 g (3 significant figures)

C = ?

T(f) = 73.86 °C (4 significant figures)

T(i) = 13.46 °C (4 significant figures)

Then, to find C, rearrange the equation:

$C \ = \frac{q}{m(T_{f} \ - \ T_{i})}$

Plug in the values to the equation above to get the value of C.

$C \ = \ \frac{22974 \ J}{96.5 \ g \ (73.86 \ \ -13.46 \°C)} \\C \ = \ \frac{22974 \ J}{96.5 \ g \ (60.4\°C)} \\C \ = \ \frac{22974 \ J}{5828.6 \ g -\°C} \\C \ = \ 3.941598 \ \frac{J}{g -\°C} \\$

Since the least number of significant figures in the given is 3, then the final answer must have 3 significant figures, too. Therefore,

$\boxed {C = 3.94 \ \frac{J}{ g -\°C}}$

<u></u>

<u>Learn More: </u>

1. Learn more about heat capacity brainly.com/question/8828503

2. Learn more about calorimetry brainly.com/question/8168263

3. Learn more about heat of reaction brainly.com/question/10122365

<u>Keywords:</u> heat capacity, specific heat, calorimetry

4 0

3 years ago

What is the mass of 2.3 moles of MgCl2?

lana66690 [7]

The mass of MgCl2 is 95.211g/mol so one mole equals 95.211 it’s asking for the mass of 2.3 which is 218.9853

6 0

3 years ago

The following is known as the thermite reaction: 2Al(s)+Fe2O3(s)→Al2O3(s)+2Fe(s) This highly exothermic reaction is used for wel

Colt1911 [192]

Answer:

$\Delta H_{rxn}=-847.6\ KJ/mol.$

Explanation:

The balanced chemical equation is:

$2Al(s)+Fe_2O_3(s)-->Al_2O_3+2Fe(s)$

Now, standard values of $\Delta H_f\ of\ all\ participants\ of\ reaction.$

$\Delta H_f(Al_2O_3)=-1669.8\ KJ/mol\\\Delta H_f(Fe_2O_3)=-822.2\ KJ/mol\\\Delta H_f(Al(s))=0\ KJ/mol\\\Delta H_f(Fe(s))=0\ KJ/mol\\$

Now, We know $\Delta H_{rxn}=\Delta H_{products}-\Delta H_{reactants}$

Putting all values of $\Delta H_f$ to above equation.

We get,

$\Delta H_{rxn}=-847.6\ KJ/mol.$

Hence, this is the required solution.

6 0

3 years ago

Which of the following is an example of a change from gravitational potential

Elenna [48]

Answer:

The speed of a roller coaster increases as gravity pulls it downhill and is greatest at its lowest point. Viewed in terms of energy, the roller-coaster-Earth system's gravitational potential energy is converted to kinetic energy

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3 years ago

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