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rewona [7]
4 years ago
12

Omar was paid on Friday. On Saturday he spent 1/4 of his pay and on Sunday he bought a new smartphone with 2/3 of the remainder.

After spending $15 on dinner, Omar had 20% of his pay left. What was Omar paid on Friday?
please explain how to set up the equation to solve the problem
Mathematics
1 answer:
nasty-shy [4]4 years ago
3 0

Answer:

Friday: 300 dollars

Step-by-step explanation:

Let Omar's pay on Friday = x

Friday:     x

Saturday:  1/4 x was spent.

Sunday:  2/3 *(x - (1/4)x ) = 2/3 * (3/4x) = (2*3/(3*4)x = (6/12)x = 1/2x

Dinner:  15 dollars

Remainder = 20% x = 20/100 x = 0.2x

x - (1/4x + 1/2(x) + 15) =  0.2x          Combine like terms on the left  

x - (3/4x + 15) = 0.2x                       Remove the brackets

x - (3/4)x - 15 =  0.2x                       Combine like terms on the left

(1/4)x - 15 = 0.2x                             Change 1/4 to a decimal

0.25x - 15 = 0.2x                            Subtract 0.25x from both sides

0.25x - 0.25x - 15 = 0.2x - 0.25x  Combine

- 15 = - 0.05x                                   Divide by - 0.05

-15 /-0.05 = - 0.05 x/ 0.05

300 = x

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On a coordinate plane, a parabola opens down. It has an x-intercept at (negative 5, 0), a vertex at (negative 1, 16), a y-interc
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Step-by-step explanation:

Domain is all the x's and range is all the y's. There's no reason why you couldn't pop any x into the given equation and calculate it and get a number out. So literally ANY x can be used and found on this graph. So the domain is all real numbers, one of the first two answers is going to be the right one. Now, the range is all the y's on the graph. The problem says that the parabola opens down, which means it has a highest point. There is no graph above that point. That's the point (-1, 16). So 16 is the highest y-value you can find on the graph. All the rest of the y's are smaller. The range is all the y's such that the y's are 16 and smaller...in math that's written {y | y <= 16} So the second answer is the right one.

5 0
3 years ago
the sum of three numbers is 79. The second number is 5 times the first, while the third is 16 more than the first. Find the numb
swat32
Let the 1st number be x; 2nd number be y; 3rd number be z.

x + y + z = 79

x = number we are looking for.
y = x * 5 ==> 5 times the first
z = x + 16 ==> 16 more than the first

Therefor,

x + (x * 5) + (x+16) = 79

1st step, multiply the 2nd number: x * 5 = 5x

x + 5x + x + 16 = 79

Add all like numbers:

7x + 16 = 79

To get x, transfer 16 to the other side and change its sign from positive to negative.

7x = 79 - 16
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To get x, divide both sides by 7

7x/7 = 63/7
x = 9

To check. Substitute x by 9.

x + (x * 5) + (x+16) = 79

9 + (9 * 5) + (9 + 16) = 79
9 + 45 + 25 = 79
79 = 79 equal. value of x is correct.

3 0
4 years ago
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Julli [10]
The two equations should be x+y=45 and 1.2x+y=52. Plug in x=35 y=10 into the second equation... then plug in x=25 and y=20 in the second equation
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