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3 years ago

HELP THIS IS A EMERGENCY please tell me all of it (it’s for my cousin in 5th grade)

Mathematics

2 answers:

VLD [36.1K]3 years ago

7 0

2.82 + 3.44 + 4.15 = _ . _

0.55 + 0.15 + 0.05 = _ . _ _

0.72 - 0.39 = _ . _ _

kkurt [141]3 years ago

6 0

3) Add 2.82, 3.44, and 4.15. Then round it so it looks like this : #.#

4) Add 0.55, 0.15, 0.40, and 0.05 all together

5) Subtract 0.39 from 0.72.

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HELP PLEASE I WILL GIVE BRAINLIEST

Andrei [34K]

Answer:

The slope intercept form is y = mx + b, where b is the y-intercept. In the equation y = 2x - 1, the y-intercept is -1. So, if you have an equation like y = 4x, there is no "b" term. Therefore, the y-intercept is zero, and the line passes through

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2 years ago

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Please help me and show your work

morpeh [17]

Answer:

Step-by-step explanation:

y = 3x + 4

Plugin x = 3 in the equation,

y = 3*3 + 4

= 9 + 4

y = 13

Plugin x = 4 in equation,

y = 3*4 + 4

= 12 + 4

y = 16

Plugin x = 5 in the equation,

y = 3*5 + 4

= 15 + 4

y = 19

2) y =x - 7

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y = 10 - 7

y = 3

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y = 15 - 7

y = 8

Plugin x = 20 in the equation

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y = 13

6 0

2 years ago

what is the vomume of the box with a height of 3/2 inches, a length of 7/2 inches, and a width 5/2 inches

JulsSmile [24]

Answer:

105/8 inch^3

Step-by-step explanation:

7/2*5/2*/3/2 = 105/8

8 0

3 years ago

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Plzzzz i will give you brainliest

geniusboy [140]

Answer:

B) 11.8

Step-by-step explanation:

First write in 4 for x and 2 for y

Then multiply 1.3 times 6 (4+2) and subtract 2-6

Your expression should now be 7.8 +4

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3 years ago

Find the equation of the line perpendicular to y = 3x + 6 and containing the point (-9,-5).

neonofarm [45]

The equation of the line perpendicular to y = 3x + 6 and containing the point (-9,-5) is $y = \frac{-1}{3}x - 8$

Solution:

Given that line perpendicular to y = 3x + 6 and containing the point (-9, -5)

We have to find the equation of line

The slope intercept form is given as:

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Let us first find the slope of line

The given equation of line is y = 3x + 6

On comparing the given equation of line y = 3x + 6 with eqn 1, we get,

m = 3

Thus the slope of given equation of line is 3

We know that product of slopes of given line and slope of line perpendicular to given line is equal to -1

Slope of given line $\times$ slope of line perpendicular to given line = -1

$3 \times \text{ slope of line perpendicular to given line }= -1$

$\text{ slope of line perpendicular to given line } = \frac{-1}{3}$

Let us now find the equation of line with slope $m = \frac{-1}{3}$ and containing the point (-9, -5)

Substitute $m = \frac{-1}{3}$ and (x, y) = (-9, -5) in eqn 1

$-5 = \frac{-1}{3}(-9) + c\\\\-5 = 3 + c\\\\c = -8$

Thus the required equation of line is:

Substitute $m = \frac{-1}{3}$ and c = -8 in eqn 1

$y = \frac{-1}{3}x - 8$

Thus the required equation of line perpendicular to given line is found

6 0

3 years ago