In equation, let x be the number of male students
a be the number of adults
y be the number of female students.
x= 7a+1
a= x/7 -1
y= x/2 or (7a + 1)/ 2
a + b = 82, let b be the number of students.
a + (x + y) = 82
a + [7a+1 + (7a+1)/2] = 82
a + [{2(7a+1) + 7a+1} / 2] = 82
a + [(14a +2 + 7a +1) / 2] = 82
a + [(21a + 3) / 2] = 82
(2a+ 21a + 3) / 2 = 82
(23a + 3) / 2 = 82
23a + 3 = 164
23a = 164 -3
23a = 161
a = 7
x = 7(7) +1, 49+1 = 50 male students
y=x/2, 50/2, 25 female students
50(male students) + 25(female students) + 7 (adults) = 82
Answer:
2x+7
Step-by-step explanation:
To Simplify an Expression , we combine Like-Terms
So for our Question , we have Terms with x and Constant Term
Combine Terms with x : 5x-2x-x=2x
Constant Term : 7
Then 5x-2x+7-x = 2x+7
Answer:
(ones)2 (tenths)2.4 (hundredths)2.38
Step-by-step explanation:
Just sayin', you COULD use Google's calculator....
-5 or more, round the next number up.
-5 or less round the next number down.
Answer:
C. √2 - 1
Step-by-step explanation:
If we draw a square from the center of the large circle to the center of one of the small circles, we can see that the sides of the square are equal to the radius of the small circle (see attached diagram)
Let r = the radius of the small circle
Using Pythagoras' Theorem 
(where a and b are the legs, and c is the hypotenuse, of a right triangle)
to find the diagonal of the square:
So the diagonal of the square = 
We are told that the radius of the large circle is 1:
⇒ Diagonal of square + r = 1
Using the quadratic formula to calculate r:
As distance is positive, 
only
