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lozanna [386]
3 years ago
9

What is the line of symmetry for the parabola whose equation is y = x2 - 12x + 7?

Mathematics
1 answer:
Pavel [41]3 years ago
3 0

Answer:

x = 6

Step-by-step explanation:

Please write this as  y = x^2 - 12x + 7 to indicate the exponentiation.

The coefficients of these three terms are a, b and c:  1, -12 and 7.

The equation of the axis (line) of symmetry is

        -b           -(-12)

x = ---------  =  -----------  = 6

         2a           2(1)

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PLS HELP ME THIS IS HARD
SOVA2 [1]

Answer:

1 dollar is equal to 0.75 E

Step-by-step explanation:

120$ = 90 e -----> 4$ = 3E

250$ = 187.50 e -----> 4$ = 3E

400$ = 300 e -----> 4$ = 3E

----------------------------------

from this we know 4$ = 3E

1 E = 4$/3

1 E = 1.33...$

---------------------

1 $ = 3/4 E

1 $ = 0.75 E

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1.33...$ dollars is equal to 1 E and

1 $ is equal to 0.75 E

-----------------------------------

90 x 1.33... =120

187.50x1.33...= 250

300 x 1.33... = 400

--------------------------

4 0
3 years ago
An electric current, I, in amps, is given by I=cos(wt)+√8sin(wt), where w≠0 is a constant. What are the maximum and minimum valu
exis [7]
Take the derivative with respect to t
- w \sin(wt) + \sqrt{8} w cos(wt)
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
0 = -w \sin(wt) + \sqrt{8} w cos(wt)
divide by w
0 =- \sin(wt) + \sqrt{8} cos(wt)
we add sin(wt) to both sides

\sin(wt)= \sqrt{8} cos(wt)
divide both sides by cos(wt)
\frac{sin(wt)}{cos(wt)}= \sqrt{8}   \\  \\ arctan(tan(wt))=arctan( \sqrt{8} ) \\  \\ wt=arctan(2 \sqrt{2)} OR\\ wt=arctan( { \frac{1}{ \sqrt{2} } )
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
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the absolute max and min will be

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since 2npi is just the period of cos
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substituting our second soultion we get
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since 2npi is the period
I=cos(2arctan( \frac{1}{ \sqrt{2}} ))= \frac{1}{3}
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minimum value =- \frac{1}{3}


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