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Allushta [10]
4 years ago
8

Graph ​ y+6=4/5(x+3) ​ using the point and slope given in the equation. Use the line tool and select two points on the line.

Mathematics
1 answer:
Anuta_ua [19.1K]4 years ago
7 0

Answer:

The points are (-3,-6) and (2,-2)

Step-by-step explanation:

I took the test got it wrong and it showed me the right answer lol

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How do you solve (7^-1)^-1 and 5^2 * 5^4 * 5^-3
Katyanochek1 [597]

Answer:

Step-by-step explanation:

exponents raised to a - power  is an inverse function probably not the right word

       a^-b    =  1/(a^b)     example       4^-2   = 1/(4^2)     =  1/16

so   (7^-1)^-1  is a double inverse which is back to the original number  7

      inverted 7 twice

      (7^-1)^-1     = (1/7)^-1     =  1/(1/7)     =   7     trust me or use your calculator

since the coeffients are the same  just add the powers...  some exponent rule

     5^2 * 5^4 * 5^-3   = 5^(2+4-3)   = 5³

here is it written out

5^2 * 5^4 * 5^-3    = 5²  ×   5^4   ×  5^-3    =   (5×5) × (5×5×5×5)  × (1/5×1/5×1/5)

    5×5 × 5× (5×5×5  × 1/5×1/5×1/5)           (5×5×5  × 1/5×1/5×1/5)  = 1

    5×5×5    = 5³

   so

7 0
3 years ago
5 (x+5) + 2 (x+10)<br> can you help me
Rainbow [258]
The answer is 3x+5. The work is below

7 0
4 years ago
What is equivalent to 3√125 ^x?
In-s [12.5K]

Answer:

Option D) ((125)^{\frac{1}{3}})^x

Step-by-step explanation:

We are given the following in the question:

(^3\sqrt{125})^x

We have to write and equivalent expression for the same.

Exponential properties:

^3\sqrt{a} = a^{\frac{1}{3}}\\(a^x)^y = a^{xy}

Using the above properties, we can write:

(^3\sqrt{125})^x\\=((125)^{\frac{1}{3}})^x\\=(125)^{\frac{x}{3}}

Thus, the correct option is

Option D) ((125)^{\frac{1}{3}})^x

4 0
3 years ago
What is the most accurate representation of the area of a plot measuring 11.7cm by 15.4cm ?
Aleks04 [339]
Area=width*height
area=(11.7)*(15.4)
area=180.18cm^2
7 0
3 years ago
[6x(5-3)+9]-5 with step by step
Arada [10]

Answer: 10

Step-by-step explanation: [30-24+9]=15-5=10

7 0
3 years ago
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