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Varvara68 [4.7K]
4 years ago
10

(r, 3), (5, 9), m = 2

Mathematics
1 answer:
Maurinko [17]4 years ago
5 0

Answer:

r = 2

Step-by-step explanation:

use slope formula to find r

(r, 3) (5, 9)  m = 2

y₂ - y₁ / x₂ - x₁ = m (Formula)

9 - 3 / 5 - r = 2 (use the points given then subtract 9 - 3)

6 / (5 - r) = 2 / 1 [Cross Multiply--2( 5- r ) = 6 x 1 ]

10 - 2r = 6 (solve equation)

-2r = -4

r = 2





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Hi there can anyone help me with this question please
forsale [732]
Mean means average, so you would add the numbers up and divide by the amount of numbers in the set. 
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4 years ago
Rewrite the expression 4+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B16-%284%29%285%29%7D" id="TexFormula1" title="\sqrt{16-(4)(
Inessa05 [86]

Answer:

2+i

Step-by-step explanation:

Given the expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}

To find:

The expression of above complex number in standard form a+bi.

Solution:

First of all, learn the concept of i (pronounced as <em>iota</em>) which is used to represent the complex numbers. Especially the imaginary part of the complex number is represented by i.

Value of i =\sqrt{-1}.

Now, let us consider the given expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-(4\times 5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-20}}{2}\\\Rightarrow \dfrac{4+\sqrt{-4}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)(4)}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)}\sqrt4}{2}\\\Rightarrow \dfrac{4+\sqrt4i}{2} \ \ \ \ \ (\because \sqrt{-1} =i) \\\Rightarrow \dfrac{4+2i}{2}\\\Rightarrow 2+i

So, the given expression in standard form is 2+i.

Let us compare with standard form a+bi so we get a =2, b =1.

\therefore The standard form of

\dfrac{4+\sqrt{16-(4)(5)}}{2}

is: \bold{2+i}

8 0
3 years ago
I need sum help please and thanks :)
Leona [35]

Answer:

6/16n is your answer I think

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Damm [24]
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