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VLD [36.1K]
3 years ago
14

Transversal CD cuts parallel lines PQ and RS at points X and Y, respectively. Points P and R lie on one side of line CD, while p

oints Q and S lie on the other side. If m∠PXY = 64.36°, what is m∠RYX?

Mathematics
1 answer:
Lilit [14]3 years ago
3 0

This problem is solved better well when given the drawing or the figure. It may have been given and you forgot to attach it in the question. However, so that we can solve this now, I drew the figure on my own (see the attached pic).

We can see from the figure that two parallel lines are intersected by a straight line. This type of scenario creates special angles. Angle PXY and angle RYX are called alternate interior angles since they are on the interior opposite sides of the cut.

By virtue of alternating interior angles, angle PXY and angle RYX are congruent hence:

m∠RYX = m∠PXY

m∠RYX = 64.36°

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Hannah says that 2.11 is a rational number. Gus says that 2.11 is a repeating decimal. Who is correct and why?
shusha [124]

Answer

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3 years ago
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A shipment of 50 precision parts including 4 that are defective is sent to an assembly plant. The quality control division selec
natali 33 [55]

Answer:

0.3968 = 39.68% probability this shipment passes inspection.

Step-by-step explanation:

The parts are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

50 parts means that N = 50

4 defective means that k = 4

10 are chosen, which means that n = 10

What is the probability this shipment passes inspection?

Probability that none is defective, so:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,50,10,4) = \frac{C_{4,0}*C_{46,10}}{C_{50,10}} = 0.3968

0.3968 = 39.68% probability this shipment passes inspection.

6 0
3 years ago
solo el 20% de los empleados de la población civil que está en una base militar restringida porta su identificación personal. Si
prisoha [69]

Usando la distribución binomial, hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.

<h3>¿Qué es la distribución binomial?</h3>

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

Los parámetros son:

  • n es el número de ensayos.
  • p es la probabilidad de éxito en un ensayo
  • x es el número de éxitos

En este problema, hay que:

  • 20% de los empleados de la población civil que está en una base militar restringida porta su identificación personal, o sea p = 0.2.
  • Llegan 10 empleados, o sea, n = 10.

La probabilidad de que el guardia de seguridad encuentre al menos uno en la base militar restringida es dada por:

P(X \geq 1) = 1 - P(X = 0)

En que:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074

Por eso:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1074 = 0.8926

Hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.

Puede-se aprender más a cerca de la distribución binomial en brainly.com/question/25132113

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Answer:

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Answer:

HL

Step-by-step explanation:

Use the HL Congruence Theorem to prove that the triangles are congruent.

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