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VLD [36.1K]
4 years ago
14

Transversal CD cuts parallel lines PQ and RS at points X and Y, respectively. Points P and R lie on one side of line CD, while p

oints Q and S lie on the other side. If m∠PXY = 64.36°, what is m∠RYX?

Mathematics
1 answer:
Lilit [14]4 years ago
3 0

This problem is solved better well when given the drawing or the figure. It may have been given and you forgot to attach it in the question. However, so that we can solve this now, I drew the figure on my own (see the attached pic).

We can see from the figure that two parallel lines are intersected by a straight line. This type of scenario creates special angles. Angle PXY and angle RYX are called alternate interior angles since they are on the interior opposite sides of the cut.

By virtue of alternating interior angles, angle PXY and angle RYX are congruent hence:

m∠RYX = m∠PXY

m∠RYX = 64.36°

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PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi
Irina18 [472]

Answer:

Question 1: P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}

Question 2:

A. P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}

B. P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}

C. P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}

Step-by-step explanation:

Conditional probability is defined by

P(A|B)= \frac{P(A and B)}{P(B)}

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

Y: Championships won by the 10 - 12 years old, beeing

P ( Y)= \frac{ 4 }{ 16 }

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} }  = \frac{1}{2}

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

P ( Y)= \frac{ 4 }{ 16 }

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

P ( Z)= \frac{ 1 }{ 16 }

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

P ( Y)= \frac{ 4 }{ 16 }

Z: Championships won by the 13 - 15 years old, beeing

P ( Z)= \frac{ 1 }{ 16 }

then

P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

so

P((YorZ) and B)= \frac{3}{16}

By definition,

P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}

3 0
3 years ago
a) A battalion of soldiers wanted to have a parade forming a square design with 1,536 soldiers. Is it possible ? If not how many
Dmitrij [34]
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The greatest 4 digit number is simple. If the square root of 10,000 is 100, than, one can assume that because 100-1=99, the resulting answer of 99×99 is less than 10,000, meaning that is is 4 digits. 99×99=9,801.
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Why does dividing 5 by a decimal less than 1 give a quotient greater than 5
andrew-mc [135]
If you divide by a decimal, you are breaking apart 1 into multiple pieces and so you are trying to find how many of that size piece will fit into 5. For example if you divide by .5 (point five), there are 2 point fives in 1 so there are 10 point fives in 5. The quotient is larger.

I hope you got that...
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Nesterboy [21]

Answer:

Y=3x+16

Step-by-step explanation:

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aleksandr82 [10.1K]

Answer: 1513.

Step-by-step explanation:

This is just another way to write subtraction! So just write it as a subtraction problem.
1576-63 = 1513 ^^

7 0
2 years ago
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