Problem 7: Correct
Problem 8: Correct
Problem 9: Correct
The steps are below if you are curious
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Problem 7
S = 180*(n-2)
2340 = 180*(n-2)
2340/180 = n-2
13 = n-2
n-2 = 13
n = 13+2
n = 15
I'm using n in place of lowercase s, but the idea is the same. If anything, it is better to use n for the number of sides since S already stands for the sum of the interior angles. I'm not sure why your teacher decided to swap things like that.
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Problem 8
First find y
y+116 = 180
y+116-116 = 180-116
y = 64
which is then used to find x. The quadrilateral angles add up to 180*(n-2) = 180*(4-2) = 360 degrees
Add up the 4 angles, set the sum equal to 360, solve for x
x+y+125+72 = 360
x+64+125+72 = 360 ... substitution (plug in y = 64)
x+261 = 360
x+261-261 = 360-261
x = 99
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Problem 9
With any polygon, the sum of the exterior angles is always 360 degrees
The first two exterior angles add to 264. The missing exterior angle is x
x+264 = 360
x+264-264 = 360-264
x = 96
TWO SCREENSHOT BELOW FOR THE ANSWER
Answer:
512 is equivalent
Step-by-step explanation:
2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2=2^9
2^9=512
We are given the graph of sine function.
First, we get the amplitude
A = [6 - (-2)] / 2
A = 4
Next, we determine the period and b
T = 4 - 0 = 4
b = 2π / T
b = π/2
The original sine function was
y = 4 sin πx/2
After the transformation, the equation now is
y = 4 sin [π(x+2)/2] + 2
To find the amount of solutions, you must find the discriminant. The discriminant is b^2 - 4ac. Number 6 has 2 solutions and number 7 has 1 solution.
