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zimovet [89]
3 years ago
8

Rewrite the expression by factoring (y+7) 3y(y+7)+(y+7)

Mathematics
2 answers:
alisha [4.7K]3 years ago
7 0
(3y+2)(y+7). There you go
pogonyaev3 years ago
4 0

Answer:

(3y+2)(y+7)

Step-by-step explanation:

I think you meant (y+7)+3y(y+7)+(y+7). Anyways, we have to count the number of (y+7) there are. The first term tells us we have 1 group. The second term tell us we have 3y groups. The last term tells us we have 1 group. Therefore we have 1+3y+1 groups of y+7 which gives us (3y+2)(y+7)

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Sladkaya [172]

Answer:

See attachment

Step-by-step explanation:

Isolate y in the first inequality:

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7 0
2 years ago
Please add this problem 4 5/6 + 6/7=
sweet [91]
Convert to a mixed number:
239/42

Divide 239 by 42:
4 | 2 | 2 | 3 | 9

42 goes into 239 at most 5 times:
 | | | | 5
4 | 2 | 2 | 3 | 9
 | - | 2 | 1 | 0
 | | | 2 | 9

Read off the results. The quotient is the number at the top and the remainder is the number at the bottom:
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4 | 2 | 2 | 3 | 9 | 
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 | | | 2 | 9 | (remainder)


The quotient of 239/42 is 5 with remainder 29, so:

Answer: 5 29/42
7 0
3 years ago
Read 2 more answers
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Shkiper50 [21]

Answer:

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