We have the given I = 10^-1 and I₀ = 10^-12.
Simply plugging in the values to the equation, we have:
L = 10log(10^-1/10^-12)
L = 110 Db
The answer is D.
(I used a scientific calculator in solving for L).
7y+5-8y+6
Group like terms
7y-8y+5+6
-y+11
or 11-y
Answer:
5√2x2
Step-by-step explanation: