Each two digit number has two numbers (duh!). Let's allow the tens digit to be x and the units digit to be y. Tens digit is 3 less than the units digit: x = y-3 Original number is 6 more than 4 times the sum of the digits: 10x+y-6 = 4x + 4y This gives us simultaneous equations!First let's clear the mess: 1. x= y-32. 6x-3y=6 Substitute 1 into 2: 6(y-3) -3y =66y - 18 - 3y = 6
3y = 24y = 8 Our units digit is 8 Substitute y= 8 into 1. x = y - 3x = 5 Our tens digit is 5 Therefore, our number is 58
Answer:
(7m + 63)/3x = k
Step-by-step explanation:
<em>m=3kx/7 - 9</em>
<u><em>add 9 to both sides:</em></u>
m+ 9 = 3kx/7
<u><em>multiply both sides by 7:</em></u>
7(m+9) = 3kx
<u><em>distribute the 7:</em></u>
7m+63 = 3kx
<u><em>divide both sides by 3x:</em></u>
<u>(7m + 63)/3x = k</u>
Jabardasth question is the scale factor is 2
Answer:
3(x + 4) = 3(x) + 3(4)
3(x + 4) = 3x + 12
3x + 12 = 3x + 12
Subtract 12 from both sides
3x + 12 - 12 = 3x + 12 - 12
3x = 3x
3x - 3x = 3x - 3x
= 0
Answer:
-1 is the only answer that is greater than -5
