The new image would be (-3,6)-P
(0,5)-Q (2,2)-R
You should just be able to graph the original image by counting from the 0,0. If you need anymore help, lemme know
Answer:10,8
Step-by-step explanation:
Because
Answer:
0.1349
Step-by-step explanation:
Given that:
Sample size, n = 500
20% of 500 ; 0.2 * 500 = 100
p = 0.18 ; n = 500 ; 1 - p = 0.82
P(x ≥ 100) ;
Using the binomial probability relation :
P(x =x) = nCx * p(x)^x * (1 - p)^(n - x
P(x ≥ 100) = 500C100 * 0.18^100 * 0.82^400
P(x ≥ 100) = 0.1349



with that template in mind.
since the original or "parent" function is y = x²−4x+3, if we change the "x" argument to "x-2", we end up with a horizontal shift.
the x-2 part would be in the template the Bx+C part, with B = 1 and C = -2, or a horizontal shift to the right of 2/1 or 2 units.
since the parent function has a point at (2, -1), if we move that horizontally only to the right, we'd end up at (4, -1).
Answer: 
Step-by-step explanation:
Given
The slant height of the square pyramid is 
The length of the side of the base is 
for the square pyramid, height is given by
![\Rightarrow h=\sqrt{l^2-r^2}\quad \quad [\text{where r=}\frac{a}{2}]\\\Rightarrow h=\sqrt{25^2-7^2}\\\Rightarrow h=\sqrt{625-49}\\\Rightarrow h=\sqrt{576}\\\Rightarrow h=24\ ft](https://tex.z-dn.net/?f=%5CRightarrow%20h%3D%5Csqrt%7Bl%5E2-r%5E2%7D%5Cquad%20%5Cquad%20%5B%5Ctext%7Bwhere%20r%3D%7D%5Cfrac%7Ba%7D%7B2%7D%5D%5C%5C%5CRightarrow%20h%3D%5Csqrt%7B25%5E2-7%5E2%7D%5C%5C%5CRightarrow%20h%3D%5Csqrt%7B625-49%7D%5C%5C%5CRightarrow%20h%3D%5Csqrt%7B576%7D%5C%5C%5CRightarrow%20h%3D24%5C%20ft)
Thus, the height of the prism is