Can you please help me with this

Mathematics

1 answer:

erastova [34]3 years ago

7 0

Well there are no specific numbers, but the area of a rectangle is the length x the width, and the width is the area ÷ the length.

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$\bf \textit{hyperbolas, horizontal traverse axis }
\\\\
\cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h\pm a, k)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
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\end{cases}\\\\
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$\bf \cfrac{(x-5)^2}{81}-\cfrac{(y-1)^2}{144}=1\implies \cfrac{(x-5)^2}{9^2}-\cfrac{(y-1)^2}{12^2}=1~~
\begin{cases}
a=9\\
b=12
\end{cases}
\\\\\\
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-------------------------------\\\\
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(14,1)\\
(-4,1)
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(20,1)\\
(-10,1)
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Thanks for using Brainly! .......

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