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KatRina [158]
3 years ago
10

Help please: (n^4)^-3(n^4)^-1

Mathematics
1 answer:
8_murik_8 [283]3 years ago
7 0

Answer:

1/n^16

Step-by-step explanation:

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(Please 75 points if answerd need this is 1 min)
chubhunter [2.5K]

Answer:

(5,-4)

Step-by-step explanation:

If reflected over the x-axis, the quadrilateral would be in the fourth quadrant. N' would be at (1,-1) and P' at (6,-1). To reflect, look at the y-coordinate of the point and turn it to negative. With point Q, it's at (5,4) so we just flip the 4 to -4 and that's our point! (5,-4)

8 0
2 years ago
You went to the mall with $80 you spent 25% of your money on a pair of shorts and 65% of the remainder on sandals how much did y
Contact [7]
25% of $80=$20
$80-$20=$60 remaining after you purchased shorts
65% of %60=$39

Answer:  Sandals cost $39.00
6 0
3 years ago
96 13=13 96 what property
andrew11 [14]
Commutative property
8 0
3 years ago
Read 2 more answers
How do you put 7:5 in a statement
Evgen [1.6K]
In a survey over whom prefers orange juice and whom prefers milk, 7 kids said they liked orange juice, and 5 chose milk. 

Hope this helped :)
5 0
2 years ago
Read 2 more answers
I don’t know how to do this
stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as x approaches the edges. For example,

g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}

has two pieces, 2x+5 and x^2-10, both of which are continuous by themselves on the provided intervals. In order for g to be continuous everywhere, we need to have

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)

By definition of g, we have g(-3)=2(-3)+5=-1, and the limits are

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1

\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1

The limits match, so g is continuous.

For the others: Each of the individual pieces of f,h are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.

4 0
3 years ago
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