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KatRina [158]
3 years ago
10

Help please: (n^4)^-3(n^4)^-1

Mathematics
1 answer:
8_murik_8 [283]3 years ago
7 0

Answer:

1/n^16

Step-by-step explanation:

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3 years ago
Solve: 1/3(−6q+4)=−1/12(4q+4)
STatiana [176]

Answer:

Combine multiplied terms into a single fraction

13(−6+4)=−112(4+4)

13(−6q+4)=−112(4q+4)\frac{1}{3}(-6q+4)=\frac{-1}{12}(4q+4)31​(−6q+4)=12−1​(4q+4)

1(−6+4)3=−112(4+4)

1(−6q+4)3=−112(4q+4)\frac{1(-6q+4)}{3}=\frac{-1}{12}(4q+4)31(−6q+4)​=12−1​(4q+4)

2

Multiply by 1

3

Combine multiplied terms into a single fraction

4

Distribute

5

Multiply all terms by the same value to eliminate fraction denominators

6

Cancel multiplied terms that are in the denominator

7

Distribute

8

Subtract

16

161616

from both sides of the equation

9

Simplify

10

Add

4

4q4q4q

to both sides of the equation

11

Simplify

12

Divide both sides of the equation by the same term

13

Simplify

Show less

Solution

=1

Step-by-step explanation:

6 0
2 years ago
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