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Radda [10]
3 years ago
8

Pls help pls help plsss

Mathematics
1 answer:
uranmaximum [27]3 years ago
7 0

Answer: I'm not sure but there's some explanation..

Step-by-step explanation:

K=11

T=20

Symbol I C

Hope this helps!

*You also need a pic

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Question 15: (5 points)
Svetradugi [14.3K]

Answer:

(4,7)

Step-by-step explanation:

Given

2x - 3 < y

(x,7)

Required

Find one possible value of x

From the given parameters;

(x,7) is a possible solution of 2x - 3 < y where y= 7

Substitute 7 for y

2x - 3 < 7

Add 3 to both sides

2x - 3 + 3 < 7 + 3

2x < 10

Divide both sides by 2

2x/2 < 10/2

x < 5

The result of the inequality implies that x is less than 5; So, the possible values of x is all real numbers less than 5;

Having said that;

(4,7) is one possible coordinate of 2x - 3 < y

4 0
4 years ago
4 times 24 in disruptive property
Nataly [62]

Step-by-step explanation:

You got it right! Great job!

3 0
3 years ago
Every time Jacob mows his neighbor's lawn he gets 20 dollars. He has 70 dollars in his bank account and needs 190 dollars to buy
Butoxors [25]

Answer:

he would have to do it 6 more times

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is the product of (x 1)^2?
Viktor [21]
The product of (x1)^2 is 20
6 0
4 years ago
28 children will attend the birthday party if each child gets 2 party favors and there are 14 favors in each box how many boxes
dezoksy [38]
Hello!

So if each box has 14 favors, what we need to do is add until we have enough, or more than enough for each of the children that will be at the party to get two of them.

So to start, 14+14=28. There are 28 children going, but each child must have two favors, not one. So, we simply add on two more boxes. 28+14=42, 42+14=56. So, we need 56 favors for each child to get two. 

You could multiply to make this problem faster, but adding works out easier in my head. Sorry to drag it out!

So to make it simple, you need four boxes of favors for each child to get two.

Hope this helps, have an awesome day!
3 0
3 years ago
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