Question

Solve the following equation 4(x-3)+5=1

Answer 1

So first you multiply x and -3 by 4 to distribute, then you collect like terms so (-12+5=-7) , then you add seven to both sides and the -7+7 cancels out so you have 4x by itself, then you divide 4x/4 but it cancels out to and  8 by 4 to get x and you answer should be x=2. Hope this helped


4(x-3)+5=1
4x-12+5=1
4x-7=1
   +7  +7
4x=8
4x/4    8/4

x=2

Answer 2

4(x - 3) + 5 = 1....distribute thru the parenthesis
4x - 12 + 5 = 1....simplify
4x - 7 = 1...add 7 to both sides
4x = 1 + 7...simplify
4x = 8...divide both sides by 4
x = 8/4
x = 2 <===