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Orlov [11]
3 years ago
7

Solve the following equation 4(x-3)+5=1

Mathematics
2 answers:
Vlad1618 [11]3 years ago
6 0
So first you multiply x and -3 by 4 to distribute, then you collect like terms so (-12+5=-7) , then you add seven to both sides and the -7+7 cancels out so you have 4x by itself, then you divide 4x/4 but it cancels out to and  8 by 4 to get x and you answer should be x=2. Hope this helped


4(x-3)+5=1
4x-12+5=1
4x-7=1
   +7  +7
4x=8
4x/4    8/4

x=2

joja [24]3 years ago
3 0
4(x - 3) + 5 = 1....distribute thru the parenthesis
4x - 12 + 5 = 1....simplify
4x - 7 = 1...add 7 to both sides
4x = 1 + 7...simplify
4x = 8...divide both sides by 4
x = 8/4
x = 2 <===
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Answer:

Step-by-step explanation:

Volume of the box  =  x³ +11x² + 20x – 32        I think the ' is a typo for ³

      the width is x-1    and the height is x+8      

Find an expression for the length

       Vol = LWH    solve L

        Vol / (WH)   =  L     so

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       (x³ +11x² + 20x – 32)       I'm willing to bet (x-1) and  (x+8) are factors

                                               but I will plot the equation to find the three roots

        (x³ +11x² + 20x – 32)  = (x-1) (x+8) (x+4)

L  =  (x³ +11x² + 20x – 32) / (x-1) (x+8)

   =  (x-1) (x+8) (x+4) / (x-1) (x+8)           the (x-1) and (x+8) cancel out leaving

L =   (x + 4)

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3 years ago
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