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insens350 [35]
3 years ago
5

1. Are the distances of 220 feet and 126 feet the radii, diameters, or circumferences of the two circles? Explain.

Mathematics
2 answers:
serious [3.7K]3 years ago
7 0

Answer:

it is very lengthy question :))))(

Dahasolnce [82]3 years ago
5 0

Answer:

1. circumference because it is the perimeter of a circle

2. 220÷3.14=70.063

70.063÷2= 35.0315

round 35.0315 to the nearest tenth:

30.0 (30)

3. 126÷3.14= 40.127

40.127÷2= 20.0635

round to nearest tenth:

20.1

4.

Step-by-step explanation:

subtract:

30-20.1= 9.9

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5/4=y−14 help meeeee
Phantasy [73]

Answer:

y= 61/4

Step-by-step explanation:

-y=-14-5/4

-y=-61/4

-1(-y=-61/4)

y= 61/4

4 0
3 years ago
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Help me with this please
Alla [95]
1 mile = 1.80
Times that by 16
answer is 28.80
4 0
2 years ago
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Please please please help me with this answer
Rasek [7]

x = number of packages he bought

y = number of popsicles in each package

Here are the two equations:

xy = 54

x = 3 + y

Using the substitution method, you can solve them to find x and y.

(3 + y)y = 54,

3y + y^2 = 54

y^2 + 3y - 54 = 0

Solve the quadriatic equation:

(y +9)(y - 6) = 0

y = -9, 6.

Plug y into: xy = 54

x(-9) = 54, x = -6.

x(6) = 54, x = 9.

So he bought 9 packages of popsicles, bc you can't bye -6 packages.

3 0
3 years ago
Simplify the expression. - | -13 | =
a_sh-v [17]
Since the -13 has the absolute value signs next to it, the 13 becomes a positive, but there is a negative outside the absolute value, and the negative sign and the absolute value sign cancelled previously, so the expressions is now
-13
The absolute value signs cancel out a negative only inside the signs, not outside, so the negative sign in the outside keeps.
5 0
3 years ago
Where is (0,19) located? Quadrant I Quadrant II Quadrant III Quadrant IV X-axis Y-axis
12345 [234]
Let P(a, b) be a point on the coordinate plane. Then the following hold:


i) If a>0, b>0 then P is in the I.Quadrant.

ii) If a<0, b>0 then P is in the II.Quadrant.

iii) If a<0, b<0 then P is in the III.Quadrant.

iv) If a>0, b<0 then P is in the IV.Quadrant.

v) If a=0 and b is positive or negative, then P is on the y-axis.

vi) If b=0 and a is positive or negative, then P is on the x-axis.


Since we have: a=0, and 19 positive, then this point is on the y-axis.


Answer: y-axis
5 0
3 years ago
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