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Dima020 [189]
4 years ago
7

When a force of 30 N acts on a certain object the acceleration of the object is 5m/s2 if the force is changed to 54 N what will

be the acceleration of the object
Mathematics
1 answer:
PtichkaEL [24]4 years ago
6 0

Answer:

The correct answer is 9 m per second^{2}

Step-by-step explanation:

Force is defined by mass of an object times it's acceleration.

Let the mass of the object be m kilograms.

When a force of 30 N acts on a certain object the acceleration of the object is 5 m per second^{2}

∴ 30 = m × 5

⇒ m = 6.

If the force is changed to 54 N, let the acceleration of the object be x  m per second^{2}.

∴ 54 = m × x

⇒ x = \frac{54}{6} = 9

Thus when the force is 54 N, the acceleration of the object is 9 m per second^{2}.

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Please help me!!! 30 minutes left
Lesechka [4]

Option D:

\frac{25 a^{9} b^{10} }{6 } is equivalent to the given expression.

Solution:

Given expression:

$\frac{(5 a b)^{3}}{30 a^{-6} b^{-7}}

To find which expression is equivalent to the given expression.

$\frac{(5 a b)^{3}}{30 a^{-6} b^{-7}}

Using exponent rule: (ab)^m=a^mb^m

    $=\frac{5^3 a^3 b^{3}}{30 a^{-6} b^{-7}}

Using exponent rule: \frac{1}{a^{m}}=a^{-m}, \quad \frac{1}{a^{-m}}=a^{m}

     $=\frac{125 a^3 b^{3}a^{6} b^{7}}{30 }

     $=\frac{125 a^3 a^{6} b^{3} b^{7}}{30 }

Using exponent rule: a^{m} \cdot a^{n}=a^{m+n}

     $=\frac{125 a^{3+6} b^{3+7} }{30 }

    $=\frac{125 a^{9} b^{10} }{30 }

Divide both numerator and denominator by the common factor 5.

    $=\frac{25 a^{9} b^{10} }{6 }

$\frac{(5 a b)^{3}}{30 a^{-6} b^{-7}}=\frac{25 a^{9} b^{10} }{6 }

Therefore,  \frac{25 a^{9} b^{10} }{6 } is equivalent to the given expression.

Hence Option D is the correct answer.

4 0
3 years ago
how much cardboard would you need to construct a rectangular prism shaped box measuring 15 inches by 13 inches by 7 inches
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We know that

[surface area]=2*[area of the base]+[perimeter of the base]*height

area of the base=15*13----> 195 in²

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6 0
3 years ago
Suppose Wal-Mart stock is selling at $59 a share and Mattel stock is selling at $28 a share. Amy has a maximum of $6000 to inves
Ulleksa [173]

Answer:

88 shares of Wall-Mart stock,

a) Step-by-step explanation,  22 shares of Mattel stock. b) $192

Given:

Suppose Wall-Mart stock is selling at $59 a share and Mattel stock is selling at $28 a share.

Amy has a maximum of $6000 to invest.

She wishes to purchase four times as many shares of Wall-Mart as of Mattel.

Only whole shares of stock can be purchased.

Question asked:

a) How many shares of each will she purchase?

b) How much money will be left over?

Solution:

Selling price of each share of Wall-Mart stock = $59

Selling price of each share of  Mattel stock = $28

Let number of shares of Mattel stock purchased = x

Then, number of shares of Wall-Mart stock = 4x

Total money invested =$6000

<u>Shares of Mattel stock </u>\times<u> $28 + Shares of  Wall-Mart stock </u>\times<u> $59 = $6000</u>

28\times x+59\times4x=6000\\28x+236x=6000\\264x=6000

Dividing both sides by 264

x=22\frac{192}{264}

<em>That means, total 22 shares of Mattel stock is purchased and 192 is the money left over:-</em>

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Total amount spent on Mattel stock shares = 22 \times $28 = $616

Total amount spent on Wall-mart stock shares = 88 \times $59 = $5192

Total amount spent on both shares = $616 + $5192 = $5808

Money left over = $6000 -  $5808 = $192

a) He will purchase 88 shares of Wall-Mart stock and 22 shares of Mattel stock.

b) Money left over is $192.

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