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3 years ago

8

Trichinella spiralis the worm that causes trichinosis is a what kind of worm

1 answer:

Fudgin [204]3 years ago

8 0

It's a parasite. Hope I helped!

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A cylindrical container of garlic powder has a height of 9 cm and 1.2 times the radius of another cylindrical container of the s

andreev551 [17]

To solve this you need to find the radius of the bigger cylinder so you have to solve the equation 36π= $r^{2}$ π(9). When you solve it you end up with a radius of 2 in which you multiply by 1.2 which gives you the radius of the new cylinder which is 2.4. With the new radius you simply find the volume of the bigger cylinder which is 51.94π $cm^{3}$ .

5 0

3 years ago

What does pH measure?

Hatshy [7]

Answer:

Option D

Explanation:

Hydronium ion concentration is a measure of pH of a solution.

The mathematical equation for the same is [H3O+] = 10-pH

OR

[H3O+] = antilog (- pH)

Hence, option D is correct

4 0

3 years ago

Which of the following is a binary compound?

MrRa [10]

Answer: A. CaO

Took the test already.

3 0

3 years ago

Read 2 more answers

At a particular temperature a 2.00-L flask at equilibrium contains 2.80 ✕ 10-4 mol N2, 2.50 ✕ 10-5 mol O2, and 2.00 ✕ 10-2 mol N

zhenek [66]

Answer : The value of equilibrium constant (K) is, $5.71\times 10^4$

Explanation :

First we have to calculate the concentration of $N_2,O_2\text{ and }N_2O$

$\text{Concentration of }N_2=\frac{\text{Moles of }N_2}{\text{Volume of solution}}=\frac{2.80\times 10^{-4}mol}{2.00L}=1.4\times 10^{-4}M$

and,

$\text{Concentration of }O_2=\frac{\text{Moles of }O_2}{\text{Volume of solution}}=\frac{2.50\times 10^{-5}mol}{2.00L}=1.25\times 10^{-5}M$

and,

$\text{Concentration of }N_2O=\frac{\text{Moles of }N_2O}{\text{Volume of solution}}=\frac{2.00\times 10^{-2}mol}{2.00L}=1.00\times 10^{-2}M$

Now we have to calculate the value of equilibrium constant (K).

The given chemical reaction is:

$N_2(g)+O_2(g)\rightarrow 2N_2O(g)$

The expression for equilibrium constant is:

$K=\frac{[N_2O]^2}{[N_2][O_2]}$

Now put all the given values in this expression, we get:

$K=\frac{(1.00\times 10^{-2})^2}{(1.4\times 10^{-4})\times (1.25\times 10^{-5})}$

$K=5.71\times 10^4$

Thus, the value of equilibrium constant (K) is, $5.71\times 10^4$

7 0

4 years ago

What will be the new volume of a 250 mL sample of gas at 300 K and 1 atm if heated to 350 K at 1 atm?

AlekseyPX

The new volume of a 250 Ml sample of gas at 300k and 1atm if heated to 350 k at 1 atm is 291.67 Ml

<u>calculation</u>

This is solved using the Charles law formula since the pressure is constant.

that is V1/T1 = V2/T2 where,

V1 =250 ml

T1=300 K

V2=?

T2= 350 k

by making V2 the subject of the formula by multiplying both side by T2

V2= T2V1/T1

V2= (350 K x 250 ml) / 300K =291.67 Ml

5 0

4 years ago