a = amount invested at 13%
b = amount invested at 2%
we know the total amount invested is 8200, so if the first amount is say "a", the second amount must be the slack left from subtracting "a", namely b = 8200 - a.
we also know 13% of "a" plus 2% of "b" yielded an interest of $461 in a year.
![\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{13\% of a}}{\left( \cfrac{13}{100}\right)a\implies 0.13a}~\hfill \stackrel{\textit{2\% of b}}{\left( \cfrac{2}{100} \right)b\implies 0.02b} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Ba%5C%25%20of%20b%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20%5Cleft%28%20%5Ccfrac%7Ba%7D%7B100%7D%20%5Cright%29%5Ccdot%20b%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D~%5Chspace%7B5em%7D%5Cstackrel%7B%5Ctextit%7B13%5C%25%20of%20a%7D%7D%7B%5Cleft%28%20%5Ccfrac%7B13%7D%7B100%7D%5Cright%29a%5Cimplies%200.13a%7D~%5Chfill%20%5Cstackrel%7B%5Ctextit%7B2%5C%25%20of%20b%7D%7D%7B%5Cleft%28%20%5Ccfrac%7B2%7D%7B100%7D%20%5Cright%29b%5Cimplies%200.02b%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)

Answer:
6 laps
Step-by-step explanation:
46 Divided by 7 is 6
Answer:
1.75,0.625
Step-by-step explanation:
Given that a couple plans to have children until they get a girl, but they agree that they will not have more than three children even if all are boys.
a) The couples can have
X I girl I boy, II girl I,II boys, III girl I,II,III boys
Pr. 0.5 0.25 0.125 0.125
b) Expected no of children
=
c)Expected number of boys
= 
Answer:
D?
Step-by-step explanation:
that my opinion but if i'm wrong i apologize
Answer:
3 packages
Step-by-step explanation:
36-14=18
18/6=3
so 3 packages