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Temka [501]
3 years ago
9

The mean cost of a five pound bag of shrimp is 40 dollars with a standard deviation of 7 dollars. If a sample of 51 bags of shri

mp is randomly selected, what is the probability that the sample mean would differ from the true mean by more than 0.6 dollars? Round your answer to four decimal places.
Mathematics
1 answer:
eimsori [14]3 years ago
4 0

Answer:

P(|\bar{x}-40| > 0.6)=0.5404

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 40 dollars

Standard Deviation, σ = 7 dollars

Sample size,n = 51

We are given that the distribution of cost of shrimp is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{7}{\sqrt{51}} = 0.9801

P(sample mean would differ by true mean by more than 0.6)

P(|\bar{x}-40| > 0.6)\\\Rightarrow = 1-P(39.4

P(39.4 \leq x \leq 40.6) \\\\= P(\displaystyle\frac{39.4 - 40}{0.9801} \leq z \leq \displaystyle\frac{40.6-40}{0.9801})\\\\ = P(-0.6121 \leq z \leq 0.6121)\\= P(z \leq 0.6121) - P(z < -0.6121)\\= 0.7298 - 0.2702 =0.4596

P(|\bar{x}|-40 > 0.6)\\= 1-0.4596=0.5404

0.5404 is the required probability.

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Dmitry_Shevchenko [17]

Answer:

The graph is wrong

Step-by-step explanation:

even through it goes through the y-intercept (2) it doesn't follow the slope of -3.

4 0
3 years ago
At the end of January of last year, stock A was selling at A dollars a share, and stock B was selling a B dollars a share, where
Maslowich

Answer: a) yNA/100

b) NA(y-x)/100

c) (NA)/B

Step-by-step explanation:

a) The total amount of dollars owned by the shares' owner = N number of shares × A dollars per share = NA dollars

This total is then transferred to buy B shares which then appreciates by y%.

The amount of increase in portfolio from January to June = y% of total dollars invested = y% of NA dollars = yNA/100

b) If the shares were left with A, the increase in portfolio from January to June would be x% and = x% of the total Dollar amount = x% of NA dollars = xNA/100

How much more money made in that time would be the difference in interest, between taking the dollars to invest in share B or keeping the dollars on investment A

That is, (yNA/100) - (xNA/100) = NA(y-x)/100

c) Total dollars available after sale of the A stock = NA

Number of B stock this dollar can buy = Total dollars available/amount of B stock per share

That is, (NA)/B

QED!

3 0
3 years ago
Let X be the number of Heads in 10 fair coin tosses. (a) Find the conditional PMF of X, given that the first two tosses both lan
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Answer:

Follows are the solution to the given point:

Step-by-step explanation:

For option A:

In the first point let z be the number of heads which is available on the first two trails of tosses so, the equation is:

P(X=k | z=2 ) = \begin{pmatrix} 10-2\\ k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k}

                         = \begin{pmatrix} 8\\k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k} \ \ \ \ \ \ \ \ \  \ \\\\

                                                                                                       k= 2,3..........10For option B:

P(X=k | X \geq 2 ) =  \sum^{10}_{i=2}  \begin{pmatrix} 10-i\\ k-i\end{pmatrix} (\frac{1}{2})^{k-i} (\frac{1}{2})^{10-k}

                                                                                                k= 2,3, 4.........10

8 0
3 years ago
The number of guests per month at a large resort is given in the table below, where f(x) is the number of guests, in hundreds, x
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X = 0 ; y = 10 ; 10 = a(0) + b(0) + c
c = 10

x=2 ; y = 15 ; 15 = a(4) + b(2) + 10 ; 5 = 4a+2b
x=4 ; y=18 ; 18 = a(16) + b(4) + 10 ; 8 = 16a + 4b 

2(5) = (4a+2b)2
-
 <u>   8 = 16a + 4b
</u>    2 = -8a

a = -0.25

b = 2

y = (1/4)x^2 + 2x + 10 ; 4y = x^2 + 8x + 40
8 0
3 years ago
Read 2 more answers
Use a drawing of counters to show 5 and then +7
Rama09 [41]

red red red red red yellow yellow yellow yellow yellow yellow

hope this helps :)

3 0
3 years ago
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