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KATRIN_1 [288]
3 years ago
8

Simplify the following rational expression

Mathematics
1 answer:
Helga [31]3 years ago
5 0

Answer:

= 5 (-2y+3) / -y+3

Step-by-step explanation:

If you need more help, you can look at this website called "symbolab".

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AC has endpoints A(-1,-3.5) and C(5,-1). Point Bis on AC and is located at (0.2,-3). What is the ratio of AB/BC?
Troyanec [42]

Try this solution (see the attachment, three basic steps, the answer is marked by red colour).

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Find the values of x and y. 3x - 5 5y - 4 y + 12​
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3x - 5 | x = 1.6 repeating
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WRS is a right triangle <br> Help me hurry please
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Step-by-step explanation:

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7 0
2 years ago
Perform the indicated operation to write given polynomial in standard form: (2x^3 − 6x^2 − 7x − 2) +(x^3 +x^2 +6x − 12)
Kipish [7]

Answer:

\left(2x^3-6x^2-7x-2\right)+\left(x^3+x^2+6x-12\right)=3x^3-5x^2-x-14

Step-by-step explanation:

To add the polynomials

Remove parentheses:

\left(2x^3-6x^2-7x-2\right)+\left(x^3+x^2+6x-12\right)=2x^3-6x^2-7x-2+x^3+x^2+6x-12

Group like terms:

=2x^3+x^3-6x^2+x^2-7x+6x-2-12

Add similar elements:

=3x^3-6x^2+x^2-7x+6x-2-12\\=3x^3-5x^2-7x+6x-2-12\\=3x^3-5x^2-x-2-12\\=3x^3-5x^2-x-14

The Standard Form for writing down a polynomial is to put the terms with the highest degree first,its term of 2nd highest is 2nd etc..

In our case the standard form is  

\left(2x^3-6x^2-7x-2\right)+\left(x^3+x^2+6x-12\right)=3x^3-5x^2-x-14

3 0
3 years ago
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