Yes, not a equallateral but an issoceles
Answer:
Step-by-step explanation:
11.04 = 10(1.02)^n
1.104 = 1.02^n
ln 1.104 = ln 1.02^n
ln 1.104 = n ln 1.02
n = ln 1.104/ ln 1.02
n = 4.99630409516
4.99 can be rounded to 5.
So a reasonable domain would be 0 ≤ x < 5
PART B)
f(0) = 10(1.02)^0
f(0) = 10(1)
f(0) = 10
The y-intercept represents the height of the plant when they began the experiment.
f(1) = 10(1.02)^1
f(1) = 10(1.02)
f(1) = 10.2
(1, 10.2)
f(5) = 10(1.02)^5
f(5) = 10(1.1040808)
f(5) = 11.040808
f(1)=10(1.02)^1
f(1)=10.2
Average rate= (fn2-fn1)/(n2-n1)
=11.04-10.2/(5-1)
=0.22
the average rate of change of the function f(n) from n = 1 to n = 5 is 0.22.
Hi!
The answer is the fourth one: y=3x
Hope this was helpful to you!!!
:)))
The second one because it passes through the origin
answer:
<h2>F2= 5kN</h2>
step by step explanation
<em>Note the second diameter was used as 50cm and not 500cm</em>
given
F1=800N
D1=20cm
A1=πD1^2/4
=3.142*20^2/4
=314.2cm^2
D2= 50cm
A2=πD2^2/4
=3.142*50^2/4
=1963.75cm^2
The pressure applied on the smaller relative to the bigger end is expressed as
F1/A1=F2/A2
substitute we have
800/314.2=F2/1963.75
cross multiply we have
F2=800*1963.75/314.2
F2=1571000/314.2
F2=5000N
F2=5kN
The larger Force is 5kN
