A small plane circles the airport at Daniel Field at 1500 feet altitude before starting to land. If the airport runway is 10,000
ft from the plane, then what is the angle of depression from the plane to the runway?
1 answer:
Small plane circles the airport the angle of depression would be 180
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Answer:
the answer is: q = -2.5
Step-by-step explanation:
70 - q - q - 2q = 80
70 - 4q = 80
-4q = 10
q = -2.5
Answer:
75
Step-by-step explanation:
15 divided by .20 = 75
Congrats? But maybe post a question next time so u don’t get in trouble :)
Basically
just put the coeficinets of each variable in the apropriate row
example
ax+by=c and
dx+ey=f
would go in like this
![\left[\begin{array}{ccc}a&b&|c\\d&e&|f\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%26%7Cc%5C%5Cd%26e%26%7Cf%5Cend%7Barray%7D%5Cright%5D%20)
so
3x+1=1 and
0x-1y=5
![\left[\begin{array}{ccc}3&1&|1\\0&-1&|5\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%261%26%7C1%5C%5C0%26-1%26%7C5%5Cend%7Barray%7D%5Cright%5D%20)
D is answer